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Vera_Pavlovna [14]
2 years ago
5

Round. each to the nearest tenth 10,061

Mathematics
1 answer:
lora16 [44]2 years ago
3 0
10,060 would be the answer.
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What is an equilateral triangle
almond37 [142]

Answer:

When all sides are equal

Step-by-step explanation:

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3 years ago
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Carrie runs 11.5 miles and five hours at a study pi runs 11.5 miles in five hours at a steady pace how long does it take her to
alukav5142 [94]

dividing 11.5 by 5 gives you the unit rate, then you just multiply that answer by 2 and you should be okay

8 0
3 years ago
8 1/3 33/4 8.287 8.29 order from least to greatest
valina [46]

Answer:

33/4 - 8.287 - 8.29 - 8 1/3

----------------------------------------------------------------------------------------------------------------

pls can i get brainliest it took soo long to figure out

7 0
2 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
3 years ago
Evaluate for x=4 and y=-3 write in simplest form<br> 2y/x2
lorasvet [3.4K]

Hello from MrBillDoesMath!

Answer:

I think your formula  (2y/x2) is equivalent to

(2*y)/(x^2)      where x^2 means x-squared.

If so, then

(2*y)/(x^2) = (2*3)/(4*4) = 6/16 = 3/8

Thank you,

MrB

7 0
3 years ago
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