uh i did this wrong so uh just ignore what i said
Answer:
10 and 12
Step-by-step explanation:
let the consecutive even integers be n and n + 2 , then
n² - 64 = 3(n + 2) ← distribute parenthesis
n² - 64 = 3n + 6 ( subtract 3n + 6 from both sides )
n² - 3n - 70 = 0 ← in standard form
(n - 10)(n + 7) = 0 ← in factored form
Equate each factor to zero and solve for n
n - 10 = 0 ⇒ n = 10
n + 7 = 0 ⇒ n = - 7
Since n must be a positive even integer then n = 10 and n + 2 = 10 + 2 = 12
The 2 numbers are 10 and 12
Answer:
quotient: 152 remainder: 23
Step-by-step explanation: hope that helps :)
can i get brainliest pls?
Both fractions have the same denominator so it's going to be easy. First set up your equation:
Add the whole numbers:
Now add the fractions:
add both together:
is an improper fraction so change it:
Since 6 is one more than 5, add 1 to the whole number and subtract the numerator and denominator(6 - 5 = 1) and make the remaining the new numerator. That leaves you with 
Your answer is
The answer would be 53. This can be found by add 127 twice (xy and uz) and subtracting it from 360. This would give you 106 and you would divide it by 2 for the 2 angles left and get the answer.
