I don't know if you meant profit or markup but,
take the difference of $80 & $50 = $30
What percent of 50 is 30? It's 3/5 or 60%. So there is a 60% markup on the original price of 50$.
Answer:
-12
Step-by-step explanation:
Just sustitute the z for -4
z+z+z
-4+(-4)+(-4)
=-12
I hope this help :)
Is there a chart involved
Answer:
Step-by-step explanation:
We want to determine a 90% confidence interval for the true population mean textbook weight.
Number of sample, n = 22
Mean, u = 64 ounces
Standard deviation, s = 5.1 ounces
For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean ± z ×standard deviation/√n
It becomes
64 ± 1.645 × 5.1/√22
= 64 ± 1.645 × 1.087
= 64 ± 1.788
The lower end of the confidence interval is 64 - 1.788 = 62.21 ounces
The upper end of the confidence interval is 64 + 1.788 = 65.79 ounces
Therefore, with 90% confidence interval, the true population mean textbook weight is between 62.21 ounces and 65.79 ounces