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3 years ago

A line with a slope of – 5 passes through the points (3,n) and (4, – 5). What is the value of n?

2 answers:

5 0

Step-by-step explanation: To find n, plug all the given information into the slope formula, which is shown here: m = y₂ - y₁ / x₂ - x₁.

Since our slope or <em>m</em> equals -5, we start

by plugging a -5 in for <em>m</em> in our formula.

Now, y₂ - y₁ would be -5 - n and x₂ - x₁ would be 4 - 3.

So we have -5 = -5 - n/4 - 3.

First we would simplify 4 - 3 to get 1.

So in our next step we have -5 = -5 - n/1.

Now get rid of the fraction by multiplying both sides by 1

and since multiplying anything by 1 is itself, just cancel the 1.

So we have -5 = -5 - n.

Add 5 to both sides to get 0 = -n.

Divide both sides by -1 to get 0 = n.

So the value of n is 0.

masha68 [24]3 years ago

3 0

Answer:

n = 0

Step-by-step explanation:

slope = y2-y1/x2-x1

-5 -n / 4-3 = -5

-5 -n /1 =-5

-5 - n = -5

n = 0

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the population P (t) of a culture of bacteria is given by P (t) =-1710t +92,000t+10,000, where t is the time in hours since the

Akimi4 [234]

The question might have some mistake since there are 2 multiplier of t. I found a similar question as follows:

The population P(t) of a culture of bacteria is given by P(t) = –1710t^2+ 92,000t + 10,000, where t is the time in hours since the culture was started. Determine the time at which the population is at a maximum. Round to the nearest hour.

Answer:

27 hours

Step-by-step explanation:

Equation of population P(t) = –1710t^2+ 92,000t + 10,000

Find the derivative of the function to find the critical value

dP/dt = -2(1710)t + 92000

= -3420t + 92000

Find the critical value by equating dP/dt = 0

-3420t + 92000 = 0

92000 = 3420t

t = 92000/3420 = 26.90

Check if it really have max value through 2nd derivative

d(dP)/dt^2 = -3420

2nd derivative is negative, hence it has maximum value

So, the time when it is maximum is 26.9 or 27 hours

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3 years ago

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andriy [413]

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3 years ago

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Adam has three pennies, two dimes, and one nickel. he also has one other coin that is different from the rest of his coins. how

Hatshy [7]

Answer:

Step 1. Read the problem. Make sure you understand all the words and ideas.

Step 2. Identify what you are looking for.

Step 3. Name what you are looking for.

Step 4. Translate into an equation. Restate the problem in one sentence. Then translate into an equation.

Step 5. Solve the equation using good algebra techniques.

Step 6. Check.

Step 7. Answer the question.

Step-by-step explanation:

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3 years ago

F(x) = x^2 + 1 is limited to (0, 1, 2, 3), what is the maximum love you all of the range?

wlad13 [49]

Answer:

Step-by-step explanation:

f(x)=x^2+1

now,

f(1)=1^2+1

=1+1

4 0

3 years ago

What is the antiderivative of 3x/((x-1)^2)

Maslowich

Answer:

$\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

Step-by-step explanation:

Given

$\int \:\:3\cdot \frac{x}{\left(x-1\right)^2}dx$

$\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx$

$=3\cdot \int \frac{x}{\left(x-1\right)^2}dx$

$\mathrm{Apply\:u-substitution:}\:u=x-1$

$=3\cdot \int \frac{u+1}{u^2}du$

$\mathrm{Expand}\:\frac{u+1}{u^2}:\quad \frac{1}{u}+\frac{1}{u^2}$

$=3\cdot \int \frac{1}{u}+\frac{1}{u^2}du$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx$

$=3\left(\int \frac{1}{u}du+\int \frac{1}{u^2}du\right)$

$\int \frac{1}{u}du=\ln \left|u\right|$ ∵ $\mathrm{Use\:the\:common\:integral}:\quad \int \frac{1}{u}du=\ln \left(\left|u\right|\right)$

$\int \frac{1}{u^2}du=-\frac{1}{u}$ ∵ $\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1$

$=3\left(\ln \left|u\right|-\frac{1}{u}\right)$

$\mathrm{Substitute\:back}\:u=x-1$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)$

$\mathrm{Add\:a\:constant\:to\:the\:solution}$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

Therefore,

$\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

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3 years ago