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3 years ago

Solve: 3x - 9 = 5(x-3)

Mathematics

1 answer:

Viefleur [7K]3 years ago

3 0

Hi,

$3x - 9 = 5(x-3)\\3x - 9 - 5(x-3)= 0\\3x -9 -5x +15 =0\\6-2x=0\\6=2x\\x=3$

Have a good day.

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Of the fifth grade students 15/20 went to the book fair.Of the students who went to the book fair,12/16 bought at least one book

Vaselesa [24]

Answer:

$\frac{9}{16}$

Step-by-step explanation:

Let total number of students $=x$

Students went to the book fair:

Students went to book fair $=\frac{15}{20}\times total\ number\ of\ students=\frac{15}{20}x$

Students who bought book:

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Hence $\frac{9}{16}$ of total students bought at least one book.

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4 years ago

For what values of x is the graph of y equals negative 3 divided by the quantity 4 plus x concave downward?

Elena-2011 [213]

We are given our function as

$y=\frac{-3}{x+4}$

For finding concavity , firstly we will find second derivative

$y'=\frac{d}{dx}\left(\frac{-3}{x+4}\right)$

$=-3\frac{d}{dx}\left(\frac{1}{x+4}\right)$

$=-3\left(-\frac{1}{\left(x+4\right)^2}\right)\cdot \:1$

$y'=\frac{3}{\left(x+4\right)^2}$

now, we can find derivative again

$y''=\frac{d}{dx}\left(\frac{3}{\left(x+4\right)^2}\right)$

$=3\frac{d}{dx}\left(\left(x+4\right)^{-2}\right)$

$y''=3\left(-\frac{2}{\left(x+4\right)^3}\right)\cdot \:1$

$y''=-\frac{6}{\left(x+4\right)^3}$

now, we can know second derivative is undefined when denominator =0

so, we set denominator =0

and then we can solve for x

$x+4=0$

$x=-4$

now, we can draw a number line and locate x=-4

and then we can find sign of second derivative on each intervals

so,

Concave downward interval:

$(-4,\infty)$

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uranmaximum [27]

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ok....let me try .....

ohhhh leave it. gu

<h2>..ok bro....sorry don't be angry bjhujj</h2>

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