Answer:
Perimeter of i - 22CM
Area of i - 13CM^2
Perimeter of ii -38CM
Area of ii -66CM^2
Perimeter of iii -30CM
Area of iii- 42CM^2
Perimeter of iv - 50CM
Area of iv- 126CM^2
Step-by-step explanation:
SHAPE I:
PERIMETER = S + S + S + S + S +S
= 7 + 1 + 5 +3 +4 +2
= 22CM
AREA = Part a - 4 * 2 = 8cm^2 part B - 5 *1 = 5cm^2
Total = 8 + 5 = 13cm^2
SHAPE II:
PERIMETER = S + S + S + S + S +S
= 4 + 4 +5 + 6 + 9 + 10
= 38 CM
AREA = Part a - 5 * 10 = 50 cm^2 part B - 4 *4 =16 cm^2
Total = 50+16 =66 cm^2
SHAPE III:
PERIMETER = S + S + S + S + S +S
= 9 + 2 + 3 + 4 + 6 + 6
= 30CM
AREA = Part a - 6 * 6 = 42cm^2 part B - 3 * 2= 6cm^2
Total = 36 + 6 =42 cm^2
SHAPE IV:
PERIMETER = S + S + S + S + S +S
= 9 + 10 + 4 + 6 + 6 + 15
= 50 CM
AREA = Part a -15 * 6 = 90 cm^2 part B - 9 *4 = 36cm^2
Total = 90 + 36 = 126cm^2
HOPE THIS HELPED
Answer: Segemnt BD is congurent to segment BD. This is true based off of the reflexive property, something is equal to itself. Also i think i go to the same school as you lol
Answer:
step g
Step-by-step explanation:
it axis is giong up more than other turtle which makes more sense.
Answer:
52
Step-by-step explanation:
The team plays 20 matches.
65% of the matches, the teams wins
= 20 * 0.65
= 13 matches
15% of the matches, the games ends in draw.
= 20 * 0.15
= 3 matches
The team is expected to lose in
= 20 - 13 - 3
= 4 matches