well, what variable are you solving for? like if you're solving for x, it would be:
tg is greater than or equal to 0x
Answer:
1) There are 13 students in Jerry's study.
2) There are 39 students in Kathy's study.
3) Jerry's study is more trustworthy!
Step-by-step explanation:
1) Jerry's study is the one with the dot plot.
Now, the number of students is calculated by adding the total number of dots in the plot.
We have a total of 13 dots.
Thus, there are 13 students in Jerry's study.
2) Kathy's study is the one with the histogram.
The total number of students is gotten by adding the corresponding number of students on the y-axis for each range of distance on the x-axis.
Total number of students = 9 + 11 + 7 + 12 = 39 students
3) Jerry's study where he used a dot plot is likely to be more trustworthy because it gives exact values of the number of students for each distance represented whereas, Kathy's study where she used a histogram doesn't give exact values but just gives a range of distances for a particular number of people.
Answer:
It should be y=4x-7
Step-by-step explanation:
M is the slope meaning Δx over Δy or rise over run
So if you look at (2,2) and count up to (3,6) the rise is 4 and the run is 1 meaning the slope is 4.
B is the y- intercept so then it would just be -7.
Answer:
1436.75504 or 1372/3π cm^3
Step-by-step explanation:
The volume of a sphere can be found using:
V = 4/3 πr^3
We know the radius is 7, so we can substitute 7 in for r
V = 4/3 π7^3
Evaluate the exponent
V = 4/3 π 343
If we want the answer in terms of pi, multiply the two other numbers, that are not pi: 4/3 and 343.
v= (4/3*343)π
v=1372/3π
If we want an exact answer, multiply 1372/3 and pi
v=1436.75504
So, the volume is 1436.75504 or 1372/3 π cm^3
Since, each side of the fence should have the 1 3/4 feet wide decorative piece, the width of the fence should be subtracted by 2 pieces (1 3/4 feet)
= 26.5 feet
Then, divide the remaining width by 4.5 feet and the answer is 5.88. Thus, approximately 5 pieces of the 4 1/2 feet should be installed.
