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ZanzabumX [31]
3 years ago
11

Can you write a real world problem that uses Pythagorean theorem ?

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
6 0

1) Road Trip: Let’s say two friends are meeting at a playground. Mary is already at the park but her friend Bob needs to get there taking the shortest path possible. Bob has two way he can go - he can follow the roads getting to the park - first heading south 3 miles, then heading west four miles. The total distance covered following the roads will be 7 miles. The other way he can get there is by cutting through some open fields and walk directly to the park. If we apply Pythagoras's theorem to calculate the distance you will get:

(3)<span>2 </span>+ (4)2 =

9 + 16 = C2

√25 = C

5 Miles. = C

Walking through the field will be 2 miles shorter than walking along the roads. .

2) Painting on a Wall: Painters use ladders to paint on high buildings and often use the help of Pythagoras' theorem to complete their work. The painter needs to determine how tall a ladder needs to be in order to safely place the base away from the wall so it won't tip over. In this case the ladder itself will be the hypotenuse. Take for example a painter who has to paint a wall which is about 3 m high. The painter has to put the base of the ladder 2 m away from the wall to ensure it won't tip. What will be the length of the ladder required by the painter to complete his work? You can calculate it using Pythagoras' theorem:

(5)<span>2 </span>+ (2)2 =

25 + 4 = C2

√100 = C

5.3 m. = C

Thus, the painter will need a ladder about 5 meters high.

3) Buying a Suitcase: Mr. Harry wants to purchase a suitcase. The shopkeeper tells Mr. Harry that he has a 30 inch of suitcase available at present and the height of the suitcase is 18 inches. Calculate the actual length of the suitcase for Mr. Harry using Pythagoras' theorem. It is calculated this way:

(18)<span>2 </span>+ (b)2 = (30)2

324 + b2 = 900

B2 = 900 – 324

b= √576

= 24 inches

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The weight of an organ in adult males has a bell-shaped distribution with a mean of 310 grams and a standard deviation of 25 gra
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Answer:

About 68% of organs will be between 300 grams and 320 grams, about 95% of organs will be About 68% of organs will be between 300 grams and 320 grams, About 68% of organs will be between 300 grams and 320 grams, about 95% of organs will be between 280 grams and 360 grams, the percentage of organs weighs less than 280 grams or more than 360 grams is 5%, and the percentage of organs weighs between 300 grams and 360 grams is 81.5%.

Given :

The weight of an organ in adult males has a bell-shaped distribution with a mean of 320 grams and a standard deviation of 20 grams.

A) According to the empirical rule, using the values of mean and standard deviation:

\rm \mu-\sigma = 320-20=300 \; gramsμ+σ=320+20=320grams

Therefore, about 68% of organs will be between 300 grams and 320 grams.

B) Again according to the empirical rule, using the values of mean and standard deviation:

\rm \mu-2\times \sigma = 320-40=280 \; gramsμ−2×σ=320−40=280grams

\rm \mu+2\times \sigma = 320+40=360 \; gramsμ+2×σ=320+40=360grams

Therefore, according to the empirical rule, about 95% of organs will be between 280 grams and 360 grams.

C)

The percentage of organs weighs less than 280 grams or more than 360 grams = 100 - (The percentage of organs weighs between 280 grams and 360 grams)

The percentage of organs weighs less than 280 grams or more than 360 grams = 100 - 95 = 5%

D)

The percentage of organs weighs between 300 grams and 360 grams = 0.5 \times× ( percentage of organs weighs between 280 grams and 360 grams + percentage of organs weighs between 300 grams and 320 grams)

The percentage of organs weighs between 300 grams and 360 grams = 0.5 \times× (95 + 68)

So, the percentage of organs weighing between 300 grams and 360 grams is 81.5%.

For more information, refer to the link given below:

brainly.com/question/23017717 95% of organs will be between 280 grams and 360 grams, the percentage of organs weighs less than 280 grams or more than 360 grams is 5%, and the percentage of organs weighs between 300 grams and 360 grams is 81.5%.

Given :

The weight of an organ in adult males has a bell-shaped distribution with a mean of 320 grams and a standard deviation of 20 grams.

A) According to the empirical rule, using the values of mean and standard deviation:

\rm \mu-\sigma = 320-20=300 \; gramsμ−σ=320−20=300grams

\rm \mu+\sigma = 320+20=320 \; gramsμ+σ=320+20=320grams

Therefore, about 68% of organs will be between 300 grams and 320 grams.

B) Again according to the empirical rule, using the values of mean and standard deviation:

\rm \mu-2\times \sigma = 320-40=280 \; gramsμ−2×σ=320−40=280grams

\rm \mu+2\times \sigma = 320+40=360 \; gramsμ+2×σ=320+40=360grams

Therefore, according to the empirical rule, about 95% of organs will be between 280 grams and 360 grams.

C)

The percentage of organs weighs less than 280 grams or more than 360 grams = 100 - (The percentage of organs weighs between 280 grams and 360 grams)

The percentage of organs weighs less than 280 grams or more than 360 grams = 100 - 95 = 5%

D)

The percentage of organs weighs between 300 grams and 360 grams = 0.5 \times× ( percentage of organs weighs between 280 grams and 360 grams + percentage of organs weighs between 300 grams and 320 grams)

The percentage of organs weighs between 300 grams and 360 grams = 0.5 \times× (95 + 68)

So, the percentage of organs weighing between 300 grams and 360 grams is 81.5%.

For more information, refer to the link given below:

brainly.com/question/23017717

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Divide 6300 by 260 to get an answer of 24.23, rounded.

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