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3 years ago

List the first ten terms of a sequence whose first term is -10 and whose common difference is -2.

1 answer:

7 0

Let a(0) represent the first term; its value is -10. The next term is found by subtracting 2 from -10, obtaining -12. Each new term is created by subtracting 2 from the previous one. Thus, the formula for the nth term is

a(n) = a(0)-2(n-1), or a(n) = -10-2(n-1).

First term: -10

Second: -12

Third: -14,

....

Tenth term: a(10) = -10-2(10-1) = -10 - 18 = -28

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