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stellarik [79]
2 years ago
12

PLEASE HELP ME PLEASE PLEASE

Mathematics
1 answer:
Mnenie [13.5K]2 years ago
3 0

Answer: D: $5272.

Step-by-step explanation:

Considering that all of the information is given to you already, the only thing that you need to do is plugin 9 for n.

So the final equation will look like this: 4500(1+0.02)^9^-^1

The answer comes out to $5272.46721451 but rounding that to the nearest dollar would be answer choice D: $5272.

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REALLY NEED HELP ASAP!!!!!!!
stich3 [128]

Answer: OPTION C

Step-by-step explanation:

There are some transformations for a function f(x). Some of them are shown below:

1. If f(x)+k, the function is shifted up "k" units.

2. If f(x)-k, the function is shifted down "k" units.

3. If f(x+k), the function is shifted left "k" units.

4. If f(x-k), the function is shifted right "k" units.

In this case you know that the function "g" is the transformation of the function "f".

Observe that the function "f" intersects the y-axis at:

y=2

And the function "g" intersects the y-axis at:

y=-2

Therefore, since both functions are 4 units apart, you can conclude that the function "f" was shifted down 4 units to get the function "g".

Then, the rule that shows that transformation is:

g(x)=f(x)-4

5 0
3 years ago
He vertices of square pqrs are p -4,0 q 4,3 r 7,-5 and s -1,-18.Show that the diagonals of square pqrs are congruent perpendicul
Anit [1.1K]

Answer:

Step-by-step explanation:

The vertices of the square given are P(-4, 0), Q(4, 3), R(7, -5) and, S(-1, -18)

For this diagonal to be right angle the slope of the diagonal must be m1=-1/m2

So let find the slope of diagonal 1

The two points are P and R

P(-4, 0), R(7, -5)

Slope is given as

m1=∆y/∆x

m1=(y2-y1)/(x2-x1)

m1=-5-0/7--4

m1=-5/7+4

m1=-5/11

Slope of the second diagonal

Which is Q and S

Q(4, 3), S(-1, -18)

m2=∆y/∆x

m2=(y2-y1)/(x2-x1)

m2=(-18-3)/(-1-4)

m2=-21/-5

m2=21/5

So, slope of diagonal 1 is not equal to slope two

This shows that the diagonal of the square are not diagonal.

But the diagonal of a square should be perpendicular, this shows that this is not a square, let prove that with distance between two points

Given two points

(x1,y1) and (x2,y2)

Distance between the two points is

D=√(y2-y1)²+(x2-x1)²

For line PQ

P(-4, 0), Q(4, 3)

PQ=√(3-0)²+(4--4)²

PQ=√(3)²+(4+4)²

PQ=√9+8²

PQ=√9+64

PQ=√73

Also let fine RS

R(7, -5) and, S(-1, -18)

RS=√(-18--5)+(-1-7)

RS=√(-18+5)²+(-1-7)²

RS=√(-13)²+(-8)²

RS=√169+64

RS=√233

Since RS is not equal to PQ then this is not a square, a square is suppose to have equal sides

But I suspect one of the vertices is wrong, vertices S it should have been (-1,-8) and not (-1,-18)

So using S(-1,-8)

Let apply this to the slope

Q(4, 3), S(-1, -8)

m2=∆y/∆x

m2=(y2-y1)/(x2-x1)

m2=(-8-3)/(-1-4)

m2=-11/-5

m2=11/5

Now,

Let find the negative reciprocal of m2

Reciprocal of m2 is 5/11

Then negative of it is -5/11

Which is equal to m1

Then, the square diagonal is perpendicular

6 0
3 years ago
Which equation is a quadratic model for the data set? Hint: Use a graphing calculator or a spreadsheet program.
Ivahew [28]

The equation that model a quadratic function is:  y=0.9673x²-0.8475x+10.4334

Step-by-step explanation:

A quadratic function has the form of ;

f(x) = ax²+bx+c  where a, b and c are real numbers and a≠0

For this case, equation y=0.9673x²-0.8475x+10.4334 models a quadratic function where a>0 thus the parabola opens upwards

See attached figure below to visualize the graph

Learn More

Quadratic functions graphs: brainly.com/question/9048896

Keywords : equation, quadratic model, data set, calculator, spreadsheet program.

#LearnwithBrainly

4 0
3 years ago
Which situation could be represented by the graph?
Nady [450]
Linear functions parabola mostly things in algebra
4 0
3 years ago
What additional doubles fact can help you find 4+3? Explain how you know
Anna35 [415]

Answer:

Either 4+4=8 then take 1 away to get 7 or 3+3=6 then add 1 to get 7.

Step-by-step explanation:

5 0
2 years ago
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