To determine which of the rectangles has a different area, the areas of the four rectangles must be calculated. The rectangle with a different area is rectangle b
The dimension of the 4 rectangles are:
a. length: 4x and width: 4
b. length: 11 and width: x
c. length: 2 and width: 8x
d. length: 16x and width: 1
The area of a rectangle is:

<u>Rectangle (a)</u>


<u>Rectangle (b)</u>


<u>Rectangle (c)</u>


<u>Rectangle (d)</u>


Rectangles (a), (c) and (d) have the same area (i.e. 16x) while rectangle (b) has 11x as its area.
Hence, the rectangle with a different area is rectangle (b).
Read more about areas of rectangles at:
brainly.com/question/14383947
The number that produces a rational answer when added to 0.85 is; 193/180
<h3>How to identify rational numbers?</h3>
A rational number is an algebraic term expressed as a fraction. The fraction can also be in decimals but only if the decimal places are not repeating or not infinitely long. If they aren't, then these are called irrational numbers.
Now, let us convert 0.85 to a fraction. Thus;
0.85 = 85/100 = 17/20
From the given options, the only one that when added to 0.85 will yield a rational number is 2/9. This is because;
17/20 + 2/9 = 193/180
193/180 is a rational number.
The missing options are;
A. 2/9
B. 0.2645751311...
C. √2
D.
Read more about rational numbers at; brainly.com/question/4694420
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Answer:
13,200 feet
Step-by-step explanation:
There are 5280 feet in a mile, so multiply 5280 by 2.5
5280*2.5=13,200
So, every Wednesday, she runs 13,200 feet
Hope this helps! :)
Answer:
Step-by-step explanation:
Given
There are 52 cards in total
there are total of 13 pairs of same cards with each pair containing 4 cards
Probability of getting a pair or three of kind card=1-Probability of all three cards being different
Probability of selecting all three different cards can be find out by selecting a card from first 13 pairs and remaining 2 cards from remaining 12 pairs i.e.

for first card there are 52 options after choosing first card one pair is destroyed as we have to select different card .
For second card we have to select from remaining 12 pairs i.e. 48 cards and so on for third card.
Required Probability is 
