Answer:
14, 15
Step-by-step explanation:
For this case we have by definition, that the equation of a line in the slope-intersection form is given by:

Where:
m: It's the slope
b: It is the cutoff point with the y axis
We need two points through which the line passes to find the slope:

We found the slope:

So, the equation is of the form:

We substitute a point to find "b":

Finally, the equation is:

Answer:
Option D
Answer:
5/3 or 1.67
Step-by-step explanation:
Find the slope of the original line
3x+5y=4 Subtract 3x from both sides
5y = - 3x + 4 Divide both sides by 5
y = (-3/5)x + 4
The original line has a slope of - 3/5 or - 0.6
Find the slope of the perpendicular line
m1 * m2 = - 1
m1 = - 3/5
m2 = -1/(-3/5)
m2 = 5/3
The slope of the perpendicular line is
5/3 or 1.67
Answer:
Approximately 12.04 units.
Step-by-step explanation:
The find the distance between any two points, we can use the distance formula, which is:

We have the points (2,7) and (-6,-2). Let's let (2,7) be (x₁, y₁) and let's let (-6, -2) be (x₂, y₂). Substitute:

Subtract:

Square:

Add:

Approximate

So, the distance between (2,7) and (-6,-2) is approximately 12.04 units.
And we're done!