Answer:
Correct answer: Fourth answer As = 73.06 m²
Step-by-step explanation:
Given:
Radius of circle R = 16 m
Angle of circular section θ = π/2
The area of a segment is obtained by subtracting from the area of the circular section the area of an right-angled right triangle.
We calculate the circular section area using the formula:
Acs = R²· θ / 2
We calculate the area of an right-angled right triangle using the formula:
Art = R² / 2
The area of a segment is:
As = Acs - Art = R²· θ / 2 - R² / 2 = R² / 2 ( θ - 1)
As = 16² / 2 · ( π/2 - 1) = 256 / 2 · ( 1.570796 - 1) = 128 · 0.570796 = 73.06 m²
As = 73.06 m²
God is with you!!!
You can use this equation to find the axis of symmetry or the vertex of the quadratic equation as long as it is in standard form
X= (-b/2a)
The answer is x=2
Answer: 9483
Step by step
= 4(52)(45)+32)−5
= 4(2340+32)−5
= (4)(2372)−5
= 9488–5
= 9483
Just sub x in with 5.
So 6(5)^3+8(5) = 6 (125) + 40 = 750 + 40 = 790.
So 790
B. <span>3.408×10^8
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