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3 years ago

One–fourth of the candies in a bag of are red. If there are 24 red candies, how many candies are in the bag?

Mathematics

2 answers:

BARSIC [14]3 years ago

7 0

Answer:

Step-by-step explanation:

answer:16

VikaD [51]3 years ago

6 0

Answer:

There are 96 candies in the bag.

Step-by-step explanation:

1/4x=24

x=24/(1/4)

x=(24/1)(4/1)

x=96/1

x=96

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Solve for the missing variable.<br> 1.)<br> 80/120 =2/x

crimeas [40]

Answer:

x = 3

Step-by-step explanation:

$\frac{80}{120} = \frac{2}{x}$

Simplify, divide the numerator and denominator by the same number

$\frac{80}{120}\\$

÷ 40

$\frac{2}{3}$

$\frac{2}{3} = \frac{2}{x}$

Cross products

$2x = 2 *3\\2x = 6\\/2 /2\\\\x = 3$

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2 years ago

I NEED HELP PLEASE !!!!

Darya [45]

Answer:

a and c

Step-by-step explanation:

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2 years ago

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write an equation for a circle with a diameter that has endpoints at (-4, -7) and (-2, -5). round to the nearest tenth if necess

andrezito [222]

Answer:

The answer to your question is (x + 3)² + (y + 6)² = 2

Step-by-step explanation:

Endpoints (-4, -7) and (-2, -5)

Process

1.- Find the length of the radius

d = $\sqrt{(x2 - x1)^{2} + (y2 - y1)^{2} }$

d = $\sqrt{(-2 + 4)^{2}+ (-5 + 7)^{2} }$

d = $\sqrt{2^{2} + 2^{2} }$

d = $\sqrt{4 + 4}$

d = $\sqrt{8}$

Radius = $\frac{\sqrt{8} }{2}$ = $\sqrt{2}$

2.- Find the center

Xm = $\frac{-4 - 2}{2} = \frac{-6}{2} = -3$

Ym = $\frac{-7 - 5}{2} = \frac{-12}{2} = -6$

Center = (-3, -6)

3.- Write the equation

(x - h)² + (y - k)² = r²

(x + 3)² + (y + 6)² = ( $\sqrt{2}$ )²

(x + 3)² + (y + 6)² = 2

3 0

3 years ago

Perform the multiplication, (7x2+a2)(x2–3a2)

aksik [14]

Answer:

The given multiplied expression is

$(7x^2+a^2)(x^2-3a^2)=7x^4-20x^2a^2-3a^4$

Step-by-step explanation:

Given expression is $(7x^2+a^2)(x^2-3a^2)$

To find the multiplication of the given expression :

$(7x^2+a^2)(x^2-3a^2)$

By using the distributive property to solve the given expression as below

$(7x^2+a^2)(x^2-3a^2)=(7x^2)(x^2)+(7x^2)(-3a^2)+(a^2)(x^2)+(a^2)(-3a^2)$

$=7x^2.x^2-21x^2a^2+a^2x^2-3a^2.a^2$

$=7x^{2+2}-21x^2a^2+a^2x^2-3a^{2+2}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$=7x^4-21x^2a^2+a^2x^2-3a^4$

Adding the like terms in the above expression we get

$=7x^4-20x^2a^2-3a^4$

Therefore $(7x^2+a^2)(x^2-3a^2)=7x^4-20x^2a^2-3a^4$

Therefore the given multiplied expression is

$(7x^2+a^2)(x^2-3a^2)=7x^4-20x^2a^2-3a^4$

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3 years ago

Max has 5 apples he gives away 2 How many apples does he have left

LUCKY_DIMON [66]

If max starts with 5 apples and then gives away too hes subtracting 2 so he has 3 left
equation: 5-2=3

4 0

3 years ago