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Sergeeva-Olga [200]
3 years ago
10

Estimate the following product using scientific notation: (19)(2,120,400)

Mathematics
2 answers:
Doss [256]3 years ago
8 0

Answer:

4.03 × 10⁷

Step-by-step explanation:

Estimate the product the given number.

(19)(2,120,400)

Product : 19×2120400

Product: 40287600

now write in scientific notation.

Scientific notation: k\times 10^n

where, k is between 0 to 9 and n any integers.

If decimal move from right to left then exponent positive.

40287600 = 4.03 × 10⁷

Estimate product of given number in scientific notation is 4.03 × 10⁷

Mice21 [21]3 years ago
6 0
4.02876x10^7, im pretty sure.
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There are 52 weeks in a year. The plant runs for 12 months. How many weeks let when 52 weeks are divided by 12 months?​
xxMikexx [17]

Step-by-step explanation:

in one month , it runs for 52/12 weeks

that is 4 weeks

3 0
3 years ago
ESTION 1 Sarah buys a new piano to the value of R 12 000. After 3 years it has a reduced value of R7 500. Determine the rate of
Ksju [112]

The rate of depreciation on the reducing balance method is $12,000.

The Piano value at the beginning of 2017 is $75,000 – $15,000 = $60,000. Depreciation for 2017 is $60,000 × 0.2 = $12,000.

This is because the rate of depreciation (20% in this case) is applied to the book value, which decreases year after year.

In 2016, the book value was $75,000, but by 2017 it had dropped to $60,000. It was reduced to $48,000 a year later. Keep in mind that the depreciation rate remains constant, but it is applied to a smaller amount (i.e., book value) each year.

As a result, the amount of depreciation per year is lower.

What is Reducing value ?

The reducing installment method is another name for the reducing balance method. It is especially useful for fixed assets whose value depreciates more rapidly in the first few years of use (e.g., cars, office equipment, and small machinery).The reducing balance method of depreciation is a method of accounting for assets over time. It is also known as declining balance depreciation or diminishing balance depreciation. It is charged at a set rate, similar to the straight line method (also known as the fixed instalment method or straight line.

To Learn more about Reducing value from the given link:

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8 0
2 years ago
2 1/3 ÷ 16 please answer this ​
CaHeK987 [17]

Answer: 0.14583333333

Step-by-step explanation:

7 0
3 years ago
Ray is planning to open a video game store. He has developed the following expense breakdown for set-up and operation for the fi
Mama L [17]

Answer:

Yes

Step-by-step explanation:

35,000 + 8,000 - 12,000 - 4,000 - 3,000 - 2,400 - 20,000 is positive

3 0
3 years ago
Sali throws an ordinary fair 6 sided dice once.
xenn [34]

a) 1/6

b) 1/36

c)

1H, 2H, 3H, 4H, 5H, 6H

1T, 2T, 3T, 4T, 5T, 6T

Step-by-step explanation:

a)

The probability of a certain event A to occur is given by

p(A)=\frac{a}{n}

where

a is the number of successfull outcomes, in which event A occurs

n is the total number of possible outcomes

In this problem, the event is

"getting a 6 when throwing a dice once"

We know that the possible outcomes of a dice are six: 1, 2, 3, 4, 5, 6, so we he have

n=6

The successfull outcome in this case is only if we get a 6, so only 1 outcome, therefore

a=1

So, the probability of this event is

p(6)=\frac{1}{6}

b)

In this case instead, we are throwing the dice twice.

The two throws of the dice are independent events (one does not depend on the other): the probability that two independent events A and B occur at the same time is given by the product of the individual probabilities,

p(AB)=p(A)\cdot p(B)

where

p(A) is the probability that event A occurs

p(B) is the probability that event B occurs

Here we have:

- Event A is "getting a 6 in the first throw of the dice". We already calculated this probability in part a), and it is

p(A)=\frac{1}{6}

- Event B is "getting a 6 in the second throw of the dice". Since the dice has not changed, the probability is still the same, so

p(B)=\frac{1}{6}

Therefore, the probability of getting a 6 on both throws is:

p(66)=p(6)\cdot p(6)=\frac{1}{6}\cdot \frac{1}{6}=\frac{1}{36}

c)

In this problem, we have:

- A dice that is thrown once

- A coin that is also thrown once

The dice has 6 possible outcomes, as we stated in part a):

1, 2, 3, 4, 5, 6

While the coin has two possible outcomes:

H = head

T = tail

So, in order to find all the outcomes of the two events combined, we have to combine all the outcomes of the dice with all the outcomes of the coin.

Doing so, using the following notation:

1H (getting 1 with the dice, and head with the coin)

The possible outcomes are:

1H, 2H, 3H, 4H, 5H, 6H

1T, 2T, 3T, 4T, 5T, 6T

So, we have a total of 12 possible outcomes.

4 0
3 years ago
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