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dedylja [7]
3 years ago
7

A motor boat and a raft start traveling downstream. After 1 hour, the boat turns around and travels back until it reaches the ra

ft. If the distance traveled by the raft is 6 miles, what is the speed of the current?

Mathematics
1 answer:
Minchanka [31]3 years ago
5 0

Answer:

Speed of the current is 3 miles per hour.

Step-by-step explanation:

Raft and a motor boat starts traveling downstream at the same time from point B towards point A downstream.

Let the speed of the motorboat = v miles per hour

and speed of the current = u miles per hour

Motorboat travels downstream with the speed = (v + u) miles per hour

Distance traveled by motorboat in 1 hour (Distance AC) = (v + u)×1 miles

Now motorboat turns around and reaches point B where it meats the raft against the river stream.

Speed of motorboat against the current = (v - u) miles per hour

Let it takes to reach at point B = t hours

Distance covered AB = (v - u)t miles

From the figure attached,

Distance BC = AC - AB

6 = (v + u) - (v - u)t ------(1)

Now raft covered the distance 6 miles in (1 + t) hours with the speed = u miles per hour.

Equation will be u(t + 1) = 6 --------(2)

Now by equating both the equations

(v + u) - (v - u)t = u(t + 1)

v + u - vt + ut = ut + u

v - vt = 0

vt = v

t = 1 hours

From equation (2)

u(1 + 1) = 6

2u = 6

u = 3 miles per hour.

Therefore, speed of the current will be 3 miles per hour.

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Do this:

500/12

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So round that to 42 feet!

So yes, 500 inches is greater than 40 feet


Hope this helped you!


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there are n counters in a bag. 4 of the counters are red and the rest are blue. Ross takes a counter from the bag at random and
Ainat [17]

Answer: n = 10.

Step-by-step explanation:

In the bag, we have n counters.

4 of the counters are red.

the rest are blue, then we have:

(n - 4) blue counters.

Now, the probability that Ross takes a blue counter from the bag is equal to the quotient between the number of blue counters (n - 4) and the total number of counters, n

Then the probability is:

p1 = (n - 4)/n

Now he draws another, and it must be blue again, then we can calculate the probability in the same way as above, but he already take a blue counter, so the number of blue counters is (n - 5) and the total number of counters is (n - 1)

The probability of this event is:

p2 = (n - 5)/(n - 1)

The joint probability (the probability that Ross takes two blue counters) is equal to the product of the individual probabilities, and we know that this is equal to 1/3, then we have the equation:

1/3 = ( (n - 4)/n)*((n - 5)/(n - 1))

Now let's solve this for n.

n*(n - 1)/3 = (n - 4)*(n - 5)

(n^2 - n)/3 = n^2 - 4*n - 5*n + 20

n^2 - n = 3*(n^2 - 9*n + 20)

n^2 - n = 3*n^2 - 27*n + 60

0 = (3*n^2 - n^2) - 27*n + n + 60

0 = 2*n^2 - 26*n + 60

The two solutions of this equation can be found with Bhaskara's equation:

n = \frac{-(-26) +- \sqrt{(-26)^2 - 4*2*60} }{2*2} = \frac{26+- 14}{4}

Then the two solutions are:

n = (26 - 14)/4 = 3

This is not an option, because we know for sure that we have 4 red counters, then this option can be discarded.

The other solution is:

n = (26 + 14)/4 = 40/4 = 10

Then we have n = 10, 10 counters in total.

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What is the perimeter of a rectangle with side lengths 6x-86x−8 and 3+14x3+14x
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