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irga5000 [103]
3 years ago
7

I need help with that! Someone please help me

Mathematics
2 answers:
Elena L [17]3 years ago
6 0
What is the question. it only says 7/12, 21/24, what does that mean?
NikAS [45]3 years ago
3 0
Sorry you zoomed to much in.
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The average temperature of kopikoville was reported to be -25 last year this year the average temperature of the kopikoville ros
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A………………….,6,6,.6.65.5.95
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3 years ago
The rectangle below has an area of x^2-25x 2 −25 square meters and a length of x+5x+5 meters. What expression represents the wid
iris [78.8K]

Answer:  x - 5

Step-by-step explanation:

Since, the area of the rectangle = x^2 - 25=(x+5)(x-5)

Length of the rectangle = x+5

Let the width of the rectangle = b

Thus, the area of the rectangle = (x+5)\times b

⇒ (x+5)\times b=(x+5)(x-5)

⇒  b=\frac{(x+5)(x-5)}{(x+5)}

⇒ b=x-5

Therefore, the expression that shows the width of the rectangle = x-5

3 0
3 years ago
Suppose that weight of adolescents is being studied by a health organization and that the accompanying tables describes the prob
svet-max [94.6K]

Answer:

<em>hello your question lacks some information attached below is the complete question</em>

answer : NO

Step-by-step explanation:

Determine the probability of not selecting an obese subject in 3 trials

= P ( not obese in 3 randomly selected ) = ( 1 - 0.111 )^3

= 0.703

The probability > 0.05

hence it is insignificant therefore the answer is NO

6 0
3 years ago
Farmers know that driving heavy equipment on wet soil compresses the soil and injures future crops. Here are data on the "penetr
Sonja [21]

Answer:

Step-by-step explanation:

Given that;

Compressed Soil 2.85 2.66 3 2.82 2.76 2.81 2.78 3.08 2.94 2.86 3.08 2.82 2.78 2.98 3.00 2.78 2.96 2.90 3.18 3.16

Intermediate Soil 3.17 3.37 3.1 3.40 3.38 3.14 3.18 3.26 2.96 3.02 3.54 3.36 3.18 3.12 3.86 2.92 3.46 3.44 3.62 4.26

                            Compressed soil           intermediate soil

Mean                      2.907                              3.286

SD                          0.1414                              0.2377

Here we have,

\bar x_1 =3.286\\ \bar x_2 =2.907\\s_1 =0.2377\\ s_2 =0.1414\\n_1=19\\n_2=20

The pooled Standard deviation

s_p=\sqrt{\frac{(n_1-1)s_1^2(n_2-1)s_2^2}{n_1+n_2-2} } \\\\=0.1943

So standard error for difference in population mean is

s_{\bar x_1 - \bar x_2} = \sqrt{\frac{s_p^2}{n_1}+\frac{s_p^2}{n_2}  } \\\\=0.0623

by inputting the values we get 0.0623

Degree of freedom for t is

df = 19 + 20 - 2 = 37,

so t-critical value is 2.715.

So required confidence interval for

\mu_{1} - \mu_{2} will be

( \bar x_1 - \bar x_2) \pm t_{critical}*s_{\bar x_1 - \bar x_2}

=0.3793 \pm2.715*0.063\\\\=0.3793\pm0.1690

So required confidence interval is (0.2103 , 0.5483).

6 0
3 years ago
What is the simplest form of the expression 2x(x − 6) − 7x2 − (13x − 3)? 5x2 − 25x + 3
kirill115 [55]
2x squared +1 - 7x squared +3
8 0
3 years ago
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