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Inessa [10]
3 years ago
15

Is a rhombus a square

Mathematics
2 answers:
olga_2 [115]3 years ago
6 0
A rhombus is a quadrilateral in which all of the sides have equal length. 
A rhombus can be a square sometimes if the angles are 90<span>°. 
</span>
 



777dan777 [17]3 years ago
5 0

Sometimes, but not every time.

A rhombus can be a square, but it doesn't always have to be.

A square is a rhombus that has special, extra requirements ...
its angles must be 90°.  So every square is a rhombus, but
not every rhombus is a square.

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The ratio of 55 nickels to 33 dollars is
aleksley [76]
Well, you can write ratios in many different forms. These forms include:

55:33

55/33

55 nickels to 33 dollars.
3 0
3 years ago
Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro
strojnjashka [21]

Answer:

The missing side is B = 6.0\ cm

The missing angles are \alpha = 56.2 and \theta = 93.8

Step-by-step explanation:

Given

A = 10\ cm

C = 12\ cm

\beta = 30

The implication of this question is to solve for the missing side and the two missing angles

Represent

Angle A with \alpha

Angle B with \beta

Angle C with \theta

Calculating B

This will be calculated using cosine formula as thus;

B^2 = A^2 + C^2 - 2ACCos\beta

Substitute values for A, C and \beta

B^2 = 10^2 + 12^2 - 2 * 10 * 12 * Cos30

B^2 = 100 + 144 - 240 * 0.8660

B^2 = 100 + 144 - 207.8

B^2 = 36.2

Take Square root of both sides

B = \sqrt{36.2}

B = 6.0 <em>(Approximated)</em>

Calculating \alpha

This will be calculated using cosine formula as thus;

A^2 = B^2 + C^2 - 2BCCos\alpha

Substitute values for A, B and C

A^2 = B^2 + C^2 - 2BCCos\alpha

10^2 = 6^2 + 12^2 - 2 * 6 * 12 * Cos\alpha

100 = 36 + 144 - 144Cos\alpha

Collect Like Terms

100 - 36 - 144 = -144Cos\alpha

-80 = -144Cos\alpha

Divide both sides by -144

\frac{-80}{-144} = Cos\alpha

0.5556 = Cos\alpha

\alpha = cos^{-1}(0.5556)

\alpha = 56.2 <em>(Approximated)</em>

Calculating \theta

This will be calculated using cosine formula as thus;

C^2 = B^2 + A^2 - 2BACos\theta

Substitute values for A, B and C

12^2 = 6^2 + 10^2 - 2 * 6 * 10Cos\theta

144 = 36 + 100 - 120Cos\theta

Collect Like Terms

144 - 36 - 100 = -120Cos\theta

8 = -120Cos\theta

Divide both sides by -120

\frac{8}{-120} = Cos\theta

-0.0667= Cos\theta

\theta = cos^{-1}(-0.0667)

\theta = 93.8 <em>(Approximated)</em>

4 0
4 years ago
Round 3.46964490715 to 3 decimal places.
marin [14]
Notice, the  third decimal place is 9 in 3.469644...

and after the 469 there's a 6, that means we can round that 469 to a 470

3.470.
8 0
3 years ago
Read 2 more answers
Pls help for 50 points NO WEBSITES please help
Arlecino [84]

Answer:

Solution: 4\frac{3}{4}, 3.5, -15, 5

Not a solution: 129 and 10\frac{2}{3}

Step-by-step explanation:

20 ≥ 5 + 3x

3x + 5 ≤ 20

3x ≤ 20 - 5

3x ≤ 15

x ≤ 5

x must be LESS than or EQUAL to 5

3 0
3 years ago
Does someone know how the correct answer?? I need help
anyanavicka [17]

Answer:

(-2,1)

Step-by-step explanation:

add 3 to x,(-5 + 3 = -2) and subtract 2 from y,(3 - 2 = 1)

8 0
3 years ago
Read 2 more answers
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