Answer:
Distance of JK = 15 unit
Step-by-step explanation:
Given:
J(4,8)
K(-1,-2)
Find:
Distance of JK
Computation:
Distance = √(x₂-x₁)² + (y₂-y₁)²
Distance of JK = √(-1-4)² + (-2-8)²
Distance of JK = √25 + 100
Distance of JK = √125
Distance of JK = 15 unit
0.27
so three divided by eleven is 0.27272727272727272727272727272727........so on and so forth.
Answer:
x = 71/5 (as an improper fraction)
x = 14 1/5 (as a proper fraction
x = 14.2 (as a decimal)
Step-by-step explanation:
It's a rectangle so the diagonals are equal
7x - 9 = 2x + 62
Subtract 2x from both sides
5x - 9 = 62
Add 9 to both sides
5x = 71
Divide both sides by 5
x = 71/5 (as an improper fraction)
x = 14 1/5 (as a proper fraction
x = 14.2 (as a decimal)
Answer:
5x+8
Step-by-step explanation:
The from is the key word
That means the second term is first
6x^2 -2x +6 - (6x^2 -7x -2)
Distribute the minus sign
6x^2 -2x +6 - 6x^2 +7x +2
Combine like terms
5x+8
