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Gwar [14]
2 years ago
13

Identify whether the following equation has a unique solution, no solution, or infinitely many solutions.

Mathematics
1 answer:
lidiya [134]2 years ago
3 0

Answer:

No solution

Step-by-step explanation:

3+6=9

3-4=-1

9 doesn't equal -1 therefore no solution.

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Solve the equation for the red variable(C)in R-C=P
BARSIC [14]

If you want to solve the equation

R-C=P

for C, you can work like this: subtract P from both sides:

R-C-P = 0

Add C to both sides:

R-P=C

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Cody is selling chocolate and white chocolate candy bars for a school fundraiser. 30% of the candy bars sold have been white cho
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Morgan jogged51.2kilometersin one weekkelly jogged6 less whats my answer
Andrei [34K]
If you would like to know how many kilometers did Kelly jog that week, you can calculate this using the following steps:

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3 years ago
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You invest $12,000 at 3.8% annual interest compounded annually. How much will you have at the end of 5 years?
Serjik [45]

Answer:

The answer is 60,000.

Step-by-step explanation:

If you invest 12,000 at 3.8 annual interest.  Annual means yearly, so that's every year. 12,000 x 5 is 60,000 that's why the answer is 60,000. If the answer is incorrect or correct let me know. If it's correct, mark me as brainlest, give me a rating, or say thank you! Have A Great Day.

3 0
2 years ago
Write a number or expression in each blank space to create true equations.
Rina8888 [55]

Answer:

7(3+5)=7(3)+7(5)\\15-10=5(3-2)

Step-by-step explanation:

Both expressions are examples of the <em>distributive property</em>, which basically says "if I have <em>this </em>many groups of some size and <em>that</em> many groups of the same size, I've got <em>this </em>+ <em>that</em> groups of that size altogether."

To give an example, if I've got <em>3 groups of 5 </em>and <em>2 groups of 5</em>, I've got 3 + 2 = <em>5 groups of 5 </em>in total. I've attached a visual from Math with Bad Drawings to illustrate this idea.

Mathematically, we'd capture that last example with the equation

5(3)+5(2)=5(3+2). We can also read that in reverse: 3 + 2 groups of 5 is the same as adding together 3 groups of 5 and 2 groups of 5; both directions get us 8 groups of 5. We can use this fact to rewrite the first expression like this: 7(3+5)=7(3)+7(5).

This idea extends to subtraction too: If we have 3 groups of 4 and we take away 1 group of 4, we'd expect to be left with 3 - 1 = 2 groups of 4, or in symbols: 4(3)-4(1)=4(3-1)=4(2). When we start with two numbers like 15 and 10, our first question should be if we can split them up into groups of the same size. Obviously, you could make 15 groups of 1 and 10 groups of 1, but 15 is also the same as <em>3 groups of 5</em> and 10 is the same as <em>2 groups of 5</em>. Using the distributive property, we could write this as 15-10=3(5)-2(5)=5(3-2), so we can say that 15-10=5(3-2).

4 0
3 years ago
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