All categories

3 years ago

In the context of management functions, which of the following is true of planning?

Business

1 answer:

Doss [256]3 years ago

6 0

Answer:

d) It involves monitoring progress toward goal achievement.

Explanation:

In the planning process the goals of organization are defined after that strategies are made and tactics are decided to achieve those strategies. Work activities are then co ordinated and monitoring is done throughout the process to achieve the goals.

You might be interested in

You need some money today and the only friend you have that has any is your ‘miserly' friend. He agrees to loan you the money yo

Bingel [31]

Answer:

B. The total interest = $4.35

Explanation:

The first question to answer, is what is the present value of the annuity of the loan and then based on that the total interest can be calculated.

<h2>Present value of annuity= A x [(1-(1+r)-n)/r]*(1+r) </h2>

Where the A represents Annuity = or $20

The r represents the rate or 1.5%

and the n represents the number of periods which is 6 months

Calculating the value =

= 20 x [(1-1.015^-6)/0.015]*1.015

= 20 x [(1-0.91454219251)/0.015]*1.015

= 20*5.782644973

=$115.65

Now that the loan amount is known, the Total Interest can be calculated as follows

Total Interest= number of payments x monthly payments) - the loan amount (calculated above)

= 20 x 6 -115.65

= 120-115.65

The total interest = $4.35

8 0

3 years ago

TASHA WANTS TO BE A DOCTOR WITCH CTSO SHOULD SHE JOIN

prisoha [69]

It depends on how it fits into her schedule. If she has toddlers that don't go to school and is a single mom,no. If she is single and has no other interests,then yes.

4 0

3 years ago

Write down the observations in a dataset that consisting of the GPAs and credits taken in the current quarter for randomly selec

lozanna [386]

Answer:

EWU students

GPA

January: 3.5

February: 2.6

March: 3.6

April : 3.1

May: 3.7

June:2.8

July: 2.9

August: 2.1

September: 2.8

October: 3.1

November: 2.2

December: 2.5

Explanation:

The GPA for EWU students shows declining pattern over the past 12 months. The students have been focused on their fall internship program and the studies are neglected. The GPA of students is declining and the minimum GPA is 2.1 which has been secured in the month of August.

3 0

2 years ago

The government of an Asian country allows its currency to nominally float freely against other currencies, but the government ha

Elena L [17]

Answer: Dirty float system.

Explanation:

The dirty float system is also knowns as "managed float".

It is a floating exchange rate in which the central bank of a particular country steps in occasionally to alter the pace at which the country's currency change value. In this system, the central bank acts to prevent external economics shock and guide against its disruptive effect on the domestic economy.

4 0

3 years ago

The Beef-up ranch feeds cattle for midwestern farmers and delivers them to processing plants in Topeka,Kansas and Tulsa, Oklahom

AfilCa [17]

Answer:

a. Min Z = 2x₁ + 2.50x₂ + 3x₃

Subject to constraints :

3x₁ + 2x₂ + 4x₃ ≤ 128 .......(1)

3x₁ + x₂ + 3x₃ ≤ 160 ........(2)

x₁ + 0x₂ + 2x₃ ≤ 32 .........(3)

6x₁ + 8x₂ + 4x₃ ≤ 256 .........(4)

3x₁ + 2x₂ + 4x₃ ≥ 64 ..........(5)

3x₁ + x₂ + 3x₃ ≥ 80 ..........(6)

x₁ + 0x₂ + 2x₃ ≥ 16 ...........(7)

6x₁ + 8x₂ + 4x₃ ≥ 128 ............(8)

x₁ ≤ 15 ...........(9)

x₂≤ 15 ...........(10)

x₃ ≤ 15 ...........(11)

x₁ , x₂, x₃ ≥ 0

b. x₁ = 15 , x₂ = 9.5 , x₃ = 8.5

c. The optimal solution is Z = 79.25

Explanation:

Given - The table is as follows :

Nutrient Feed 1 Feed 2 Feed 3
A 3 2 4
B 3 1 3
C 1 0 2
D 6 8 4

The minimum requirement per cow each month is 4 pounds of nutrient A, 5 pounds of nutrient B, 1 pound of nutrient C, and 8 pounds of nutrient D. However, cows should not be fed more than twice the minimum requirement for any nutrient each month. Additionally, the ranch can only obtain 1,500 pounds of each type of feed each month. Because there are usually 100 cows at the beef-up ranch at any given time, this means that no more than 15 pounds of each type of feed can be used per cow each month.

To find - a. Formulate a linear programming problem to determine how

much of each type of feed a cow should be fed each month.

b. Create a spreadsheet model for this problem, and solve it using

Solver.

c. What is the optimal solution?

Proof -

Let feed 1 per cow per month = x₁

feed 2 per cow per month = x₂

feed 3 per cow per month = x₃

Now,

As given, The cost per pound of feeds 1,2, and 3 are $2.00, $2.50, and $3.00, respectively.

So, we have to minimize the cost , Z = 2x₁ + 2.50x₂ + 3x₃

Subject to constraints :

3x₁ + 2x₂ + 4x₃ ≤ 4(32)

3x₁ + x₂ + 3x₃ ≤ 5(32)

x₁ + 0x₂ + 2x₃ ≤ 1(32)

6x₁ + 8x₂ + 4x₃ ≤ 8(32)

∴ we get

Min Z = 2x₁ + 2.50x₂ + 3x₃

Subject to constraints :

3x₁ + 2x₂ + 4x₃ ≤ 128 .......(1)

3x₁ + x₂ + 3x₃ ≤ 160 ........(2)

x₁ + 0x₂ + 2x₃ ≤ 32 .........(3)

6x₁ + 8x₂ + 4x₃ ≤ 256 .........(4)

Now, as given

However, cows should not be fed more than twice the minimum requirement for any nutrient each month.

∴ we have

3x₁ + 2x₂ + 4x₃ ≥ $\frac{128}{2}$

3x₁ + x₂ + 3x₃ ≥ $\frac{160}{2}$

x₁ + 0x₂ + 2x₃ ≥ $\frac{32}{2}$

6x₁ + 8x₂ + 4x₃ ≥ $\frac{256}{2}$

and also

No more than 15 pounds of each type of feed can be used per cow each month.

⇒x₁ , x₂, x₃ ≤ 15

So,

The LPP model becomes

Min Z = 2x₁ + 2.50x₂ + 3x₃

Subject to constraints :

3x₁ + 2x₂ + 4x₃ ≤ 128 .......(1)

3x₁ + x₂ + 3x₃ ≤ 160 ........(2)

x₁ + 0x₂ + 2x₃ ≤ 32 .........(3)

6x₁ + 8x₂ + 4x₃ ≤ 256 .........(4)

3x₁ + 2x₂ + 4x₃ ≥ 64 ..........(5)

3x₁ + x₂ + 3x₃ ≥ 80 ..........(6)

x₁ + 0x₂ + 2x₃ ≥ 16 ...........(7)

6x₁ + 8x₂ + 4x₃ ≥ 128 ............(8)

x₁ ≤ 15 ...........(9)

x₂≤ 15 ...........(10)

x₃ ≤ 15 ...........(11)

x₁ , x₂, x₃ ≥ 0

b.)

We use simplex method calculator to solve this LPP Problem

we get

x₁ = 15 , x₂ = 9.5 , x₃ = 8.5

c.)

The optimal solution is Z = 79.25

4 0

2 years ago