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Fynjy0 [20]
3 years ago
9

" alt="6 = \frac{a}{4} + 2" align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
natta225 [31]3 years ago
7 0
It is 1 Bc if u multiple 1 times 4 and then add 2 it will give you 6welcome
Olegator [25]3 years ago
4 0
A=16 because 16/4=4
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PLEASE PLEASE HELP!!
Black_prince [1.1K]

Answer:

It is right

Step-by-step explanation:

square all sides

we have 16, 32, 48

add the two shortest sides, which equal the third side

the triangle works with the pythagorean theorem, so of course it is right :)

7 0
2 years ago
Which of the following are exterior angles? Check all that apply.
zheka24 [161]

Answer:

2, 3, 5, 6

Step-by-step explanation:

because the angles are outside

8 0
2 years ago
Krypton-91 is a radioactive substance that decays very quickly. The function Q(t)=Qoe^-kt models radioactive decay of krypton-91
Masteriza [31]
The "k" value should have units and should be negative.
k = -.07 / seconds
Half-Life = ln (.5) / k
Half-Life = ln (.5) / -.07
Half-Life = -.693147 / -.07
Half-Life = 9.9 seconds
(actually, wkpedia says half-life of Krypton 91 is 8.57 seconds)

elapsed time = half-life * log (bgng amt / end amt) / log (2)
elapsed time = 9.9 * log (100 / 10) / 0.30102999566
elapsed time = 9.9 * 1 / 0.30102999566
<span><span>elapsed time = 9.9 * 3.3219280949 </span>
</span><span><span><span>elapsed time = 32.8870881395 </span> </span> </span>
<span>elapsed time = 32.89 seconds (rounded)

Source:
http://www.1728.org/halflife.htm

</span>
6 0
3 years ago
Read 2 more answers
EASY 14 POINTS, PLEASE HELP ASAP.
jenyasd209 [6]
Well really it would have to depend on the flashlight. Is it an led bulb or a regular bulb?
5 0
3 years ago
Read 2 more answers
The function h(t)=-4.87t^2+18.75t is used to model the height of an object projected in the air, where h(t) is the height in met
rodikova [14]
Looking at the graph you can see that the domain of the function is:
 [0, 3.85]
 To find the range of the function, we must follow the following steps:
 Step 1)
 
Evaluate for t = 0
 h (0) = - 4.87 (0) ^ 2 + 18.75 (0)
 h (0) = 0
 Step 2) 
 find the maximum of the function:
 h (t) = - 4.87t ^ 2 + 18.75t
 h '(t) = - 9.74 * t + 18.75
 -9.74 * t + 18.75 = 0
 t = 18.75 / 9.74
 t = 1.925051335
 We evaluate the function at its maximum point:
 h (1.925051335) = - 4.87 * (1.925051335) ^ 2 + 18.75 * (1.925051335)
 h (1.93) = 18.05
 The range of the function is:
 [0, 18.05]
 Answer:
 
Domain: [0, 3.85]
 Range: [0, 18.05]
 option 1
3 0
3 years ago
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