Which of the following functions is graphed below?
1 answer:
The graph shows a piecewise function, meaning that different functions are shows at different intervals (ranges of x-values).
1) One of the graphs is part of a parabola, meaning the equation is quadratic (has
). That equation must be 
.
2) The other graph is a straight line, meaning it must be a linear equation. That equation must be x + 4.
Looking at the entire graph, you can see that the parabola starts from the left and ends with an open circle at x=2. An open circle means that the graph doesn't have a value at that point, x=2. The linear line starts with a filled point at x=2 and continues to the right. That means we're looking for the choice where:
1)
Since x=2 cannot be a point in the graph, and less than 2 means that the graph includes everything to the left of 2, but not including 2
2)
Since x=2 is a point in the graph, and greater than or equal to 2 means that the graph includes 2 and everything to the right of it
------
Answer: C)
1) One of the graphs is part of a parabola, meaning the equation is quadratic (has
2) The other graph is a straight line, meaning it must be a linear equation. That equation must be x + 4.
Looking at the entire graph, you can see that the parabola starts from the left and ends with an open circle at x=2. An open circle means that the graph doesn't have a value at that point, x=2. The linear line starts with a filled point at x=2 and continues to the right. That means we're looking for the choice where:
1)
Since x=2 cannot be a point in the graph, and less than 2 means that the graph includes everything to the left of 2, but not including 2
2)
Since x=2 is a point in the graph, and greater than or equal to 2 means that the graph includes 2 and everything to the right of it
------
Answer: C)
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Answer: C
the mean and the median
Step-by-step explanation:
From the attached table,
The range of group A = 5 - 0 = 5
The range of group B = 4 - 1 = 3
Difference in range is not equal to $1
The mode of A = 1
The mode of B = 3
Difference in mode is not equal to $1
The median of A = (1 + 2)/2 = 1.5
The median of B = 3
Difference = 3 - 1.5 = $1.5
The mean of A = 16/15 = 1.07
The mean of B = 40/15 = 2.67
The difference = $1.6
From the above analysis, we can therefore conclude that non of the measures are $1 greater for Group B than for Group A
The best option among the options is
the mean and the median
