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brilliants [131]
3 years ago
7

Which of the following functions is graphed below?

Mathematics
1 answer:
Paul [167]3 years ago
6 0
The graph shows a piecewise function, meaning that different functions are shows at different intervals (ranges of x-values). 

1) One of the graphs is part of a parabola, meaning the equation is quadratic (has x^{2}). That equation must be x^{2} + 4.
2) The other graph is a straight line, meaning it must be a linear equation. That equation must be x + 4.

Looking at the entire graph, you can see that the parabola starts from the left and ends with an open circle at x=2. An open circle means that the graph doesn't have a value at that point, x=2. The linear line starts with a filled point at x=2 and continues to the right. That means we're looking for the choice where:
1) x^{2} + 4  \ \textless \  2
Since x=2 cannot be a point in the graph, and less than 2 means that the graph includes everything to the left of 2, but not including 2

2) x + 4  \geq  2
Since x=2 is a point in the graph, and greater than or equal to 2 means that the graph includes 2 and everything to the right of it

------

Answer: C) y = \left \{ {{x^{2} + 4  \textless \ 2} \atop {x + 4 \: \geq \: 2}} \right.



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jolli1 [7]

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3 0
2 years ago
(5⁷)(55)x=8⁵<br>Solve Asap​
Ostrovityanka [42]
  • Calculate

\sf\longmapsto4296875x=32768

  • Divide both sides by 4296875

\sf\longmapsto \dfrac{4296875x}{4296875}  =  \dfrac{32768}{4296875}

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\sf\longmapsto \: x =  \dfrac{32768}{4296875}

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2 years ago
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The positions of two divers from the water's surface after a dive are shown:
qaws [65]
The answer is:  [C]:
____________________________________________________________
   "<span>Because –22 < –17, so –22 is farther from 0 than is –17 " .
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5 0
3 years ago
Find the volume of the solid by rotating the region bounded by y=x^3, y=8, and x=0 about the y axis.
dimulka [17.4K]

Answer:

Solution : Volume = 96/5π

Step-by-step explanation:

If we slice at an arbitrary height y, we get a circular disk with radius x, where x = y^(1/3). So the area of a cross section through y should be:

A(y) = πx^2 = π(y^(1/3))^2 = πy^(2/3)

And now since the solid lies between y = 0, and y = 8, it's volume should be:

V =  ∫⁸₀  A(y)dy (in other words ∫ A(y)dy on the interval [0 to 8])

=> π ∫⁸₀ y^(2/3)dy

=> π[3/5 * y^(5/3)]⁸₀

=> 3/5π(³√8)⁵

=> 3/5π2^5

=> 96/5π ✓

7 0
3 years ago
How do I do this I really don't understand anything here
Lera25 [3.4K]

The red arrows show that the lines are parallel, but using the stuff given you can make an equation.
its hard to explain without drawing but starting from the 60 if you can make a Z you will get alternate angles and that mean that the given equation MUST be equal to 60. So,

8x-4=60

8x=60+4

8x=64

x=64/8

x=8 (is your answer)

hope you understand


8 0
4 years ago
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