Question

The ball's height( in meters above the ground), x seconds after Amir threw it, is modeled by : h(x)=-(x-2)^2 +16 what is the height of the ball at the time its thrown?

Answer 1

Answer:

12 m

Step-by-step explanation:

Answer 2

Answer:

20 m

Step-by-step explanation:

The height of the ball in metres is given as:

$h(x) = (x-2)^2 + 16$

where xis time, in seconds.

At the instant that the ball is thrown, the time is 0 seconds. This means that the height will be h(0):

$h(0) = (0 - 2)^2 + 16\\\\\\h(0) = (-2)^2 + 16\\\\\\h(0) = 4 + 16\\\\\\h(0) = 20 m$

The height of the ball is 20 metres.