The ball's height( in meters above the ground), x seconds after Amir threw it, is modeled by : h(x)=-(x-2)^2 +16 what is the hei

Question

3 years ago

6

ght of the ball at the time its thrown?

2 answers:

IgorLugansk [536] · Answer 1 · 2022-02-03T13:19:30+03:00

7 0

Answer:

12 m

Step-by-step explanation:

Bess [88] · Answer 2 · 2022-02-03T12:08:07+03:00

Bess [88]3 years ago

3 0

Answer:

20 m

Step-by-step explanation:

The height of the ball in metres is given as:

$h(x) = (x-2)^2 + 16$

where xis time, in seconds.

At the instant that the ball is thrown, the time is 0 seconds. This means that the height will be h(0):

$h(0) = (0 - 2)^2 + 16\\\\\\h(0) = (-2)^2 + 16\\\\\\h(0) = 4 + 16\\\\\\h(0) = 20 m$

The height of the ball is 20 metres.