Answer:
16 people
Step-by-step explanation:
This is a set problem
let first session be a
let second session be b
128 people attended at least one session = a∪b
a. 3/4 attended both session 1&2 = a∩b
b. 7/8 attended session 2 = p(b) i.e population b
c x attended session 1 = p(a) i.e. population a
lets get the figures.
- For both sessions 3/4 × 128 = 96 = a∩b
- For second session 7/8 × 128 = 112 = b
- The formular is a∪b = p(a) + p(b) - a∩b
- a∪b = 128 (they at least one session)
lets substitute into the equation
let p(a) be x
128 = x + 112 - 96
128 = x + 16
x = 112 - no of people that attended the morning session.
But to find those that ONLY attended morning session
x - a∩b
112 - 96 = 16
12%
40% = 0.4
30 = 0.3
0.3 x 0.4 = 0.12
0.12 = 12%
Answer:
Same shape and Same angles.
Reciprocal just means to flip the fraction around:
6/11
11/6
