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Elena-2011 [213]

3 years ago

5

The school you want to go to has an acceptance rate of 12%. That means that 12% of the students who apply to the school get in.

The school took in 2,400 students last year. How many students applied?

2 answers:

Usimov [2.4K]3 years ago

6 0

20,000 students applied

docker41 [41]3 years ago

4 0

The answer is 200 students that applied last year

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130 students choose to attend one of three after school activities: football, tennis or running. There are 58 boys. 49 students

cestrela7 [59]

Answer: $\dfrac{27}{65}$

<u>Step-by-step explanation:</u>

There are 130 students.

There are 58 boys --> 72 girls

A) 49 chose football: 27 are girls --> 22 are boys

B) 72 girls: 24 chose running, 27 chose football --> 21 girls chose tennis

C) 27 students chose tennis: 21 are girls --> 6 are boys.

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$\large\boxed{\begin{array}{l|cc||c}&\underline{Boys}&\underline{Girls}&\underline{Total}\\Football&22&27&49\\Tennis&6&21&27\\\underline{Running}&\underline{\quad 30\quad}&\underline{\quad 24\quad}&\underline{\quad 54\quad}\\Total&58&72&130\end{array}}$

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4 years ago

Use the drop-down menus to choose steps in order to correctly solve 4k−6=-2k−16−2 for k .

Triss [41]

While there is no drop-down menu options for me to choose. I will show you how to solve this.

$\mathrm{Subtract\:the\:numbers:}\:-16-2=-18 \ \textgreater \ 4k-6=-2k-18$

$\mathrm{Add\:}6\mathrm{\:to\:both\:sides} \ \textgreater \ 4k-6+6=-2k-18+6 \ \textgreater \ Simplify$

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Simplify again.

$6k=-12 \ \textgreater \ \mathrm{Divide\:both\:sides\:by\:}6 \ \textgreater \ \frac{6k}{6}=\frac{-12}{6} \ \textgreater \ Simplify \ \textgreater \ k=-2$

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