Find a polynomial function f(x) of degree 3 with real coefficients that satisfies the following conditions.
1 answer:
Answer:
The polynomial will be .
Step-by-step explanation:
The three degree polynomial function f(x) has zeros at x = 0 and at x = 4 having multiplicity 2.
Therefore, (x - 0) and (x - 4)² will be factors of the polynomial f(x).
Hence, the polynomial will be f(x) = Ax(x - 4)² .............. (1), where A is any constant that we have to evaluate.
Now, given that f(5) = 20
So, from the equation (1) we have
20 = A(5)(5 - 2)²
⇒
Therefore, the polynomial will be (Answer)
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Use the formula of a distance between two points:
Answer:
g(t) = 10000(0.938)^t
Step-by-step explanation:
Given data:
car worth is $10,000 in 2012
car worth is $8000 in 2014
let linear function is given as
P(t) = at + b
which denote the value of car in year t
take t =0 for year 2012
at t =0, 10,000 = 0 + b
we get b = 10,000
take t =2 for year 2014
at t =2, P(2) = 2a + b
8800 = 2a + 10,000
a = - 600
Thus the price of car at year t after 2012 is given as p(t) = -600t + 10000
let the exponential function where t denote t = 0 at 2012
putting t = 0 P(0) = 10,000 we get 10,000 = ab^0
a = 10,000
putting t = 2 p = 8800
b = 0.938
g(t) = 10000(0.938)^t
Answer:
the answer is
Step-by-step explanation:
You have to find the common denominator in order to get the sum.
multiply 5 to and you get
then to double check the sum, subtract it.
hope this make sense :/