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2 years ago

I need help here are points

Mathematics

2 answers:

horsena [70]2 years ago

8 0

Answer:

3. 50

4. 1

Step-by-step explanation:

-5a + 2b - 6c

Substitute the variables, knowing that:

a = -6, b = 4, and c = -2

-5(-6) + 2(4) - 6(-2)

Multiply -5 and -6.

30 + 2(4) - 6(-2)

Multiply 2 and 4.

30 + 8 - 6(-2)

Multiply -6 and -2.

30 + 8 + 12

Add 30 and 8.

38 + 12

Add 38 and 12.

√(5x) + 2y

Substitute the variables, knowing that:

x = 5 and y = -2

√(5(5)) + 2(-2)

Multiply 5 and 5.

√(25) + 2(-2)

Multiply 2 and -2.

√(25) - 4

Take the square root of 25.

5 - 4

Subtract 4 from 5.

DaniilM [7]2 years ago

6 0

Answer:

ok when you first loaded the x y z fraction question on another page you asked for help where two people had answered saying it was 3 they were wrong the answer is 6 as 18/3 = 6 the answers below are for this question above hope this helps you also

Step-by-step explanation: QU 1 = 50 + QU 2 = 1

Qu 1) -5 a + 2b - 6c = rewrite out empty brackets for a and b and c Then step 2 is to input number's in brackets as a = -6 b = 4 and c = -2 we substitute so write out first (-5 ( )) + 2( ) - (6( )) if all polynomials are + - we show so like in bold then its easier to determine what to fill in to substitute (-5 (-6)) + 2(4) - (6(-2)) = 30 + 8 + 12 = 50 if we rewrote like this instead (-5 (-6)) + 2(4) -6(-2)) it would also be right so the answer is 50 Qu 2) sq rt 5x +2 y = (when x = 5 and y = -2) sq rt 5(5) and + 2(-2) = sq rt 25 -4 = 5 -4 = 1 Hope this helps also free worksheet info for graphs to explain things math.utah.edu/~wortman/1050-text-calp.pdf just type www in front helps all students that are struggling with graphs

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Anastaziya [24]

Answer: (60.858, 69.142)

Step-by-step explanation:

The formula to find the confidence interval for mean :

$\overline{x}\pm z_c\dfrac{\sigma}{\sqrt{n}}$ , where $\overline{x}$ is the sample mean , $\sigma$ is the population standard deviation , n is the sample size and $z_c$ is the two-tailed test value for z.

Let x represents the time taken to mail products for all orders received at the office of this company.

As per given , we have

Confidence level : 95%

n= 62

sample mean : $\overline{x}=65$ hours

Population standard deviation : $\sigma=18$ hours

z-value for 93% confidence interval: $z_c=1.8119$ [using z-value table]

Now, 93% confidence the mean time taken to mail products for all orders received at the office of this company :-

$65\pm (1.8119)\dfrac{18}{\sqrt{62}}\\\\ 65\pm4.142\\\\=(65-4.142,\ 65+4.142)\\\\= (60.858,\ 69.142)$

Thus , 93% confidence the mean time taken to mail products for all orders received at the office of this company : (60.858, 69.142)

8 0

3 years ago

which describes the number sentences? 6+0=6: Commutative Property of Addition or Identity Property of Addition

Eduardwww [97]

The identity property of addition states that a + 0 = a

Your answer is identity property of addition.

8 0

2 years ago

3 women push a stalled car. Each woman pushes with a 425 N force. What is the mass of the

iogann1982 [59]

Answer:

1,500 Kg

Step-by-step explanation:

Formual for froce is given by

force = mass * acceleration

Force exerted by 1 woman = 425 N

no. of women exerting force = 3

Force exerted by 3 woman = 425 * 3 N = 1275 N

Acceleration produced by 1275 N force = 0.85 m/s^2

Using formula force = mass * acceleration

1275 = mass * 0.85 m/s^2

=> mass = 1275/ 0.85 m/s^2 = 1,500 Kg

Thus, mass of car is 1,500 Kg.

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2 years ago

CALC- limits<br> please show your method

gladu [14]

A. Factor the numerator as a difference of squares:

$\displaystyle\lim_{x\to9}\frac{x-9}{\sqrt x-3}=\lim_{x\to9}\frac{(\sqrt x-3)(\sqrt x+3)}{\sqrt x-3}=\lim_{x\to9}(\sqrt x+3)=6$

c. As $x\to\infty$ , the contribution of the terms of degree less than 2 becomes negligible, which means we can write

$\displaystyle\lim_{x\to\infty}\frac{4x^2-4x-8}{x^2-9}=\lim_{x\to\infty}\frac{4x^2}{x^2}=\lim_{x\to\infty}4=4$

e. Let's first rewrite the root terms with rational exponents:

$\displaystyle\lim_{x\to1}\frac{\sqrt[3]x-x}{\sqrt x-x}=\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}$

Next we rationalize the numerator and denominator. We do so by recalling

$(a-b)(a+b)=a^2-b^2$
$(a-b)(a^2+ab+b^2)=a^3-b^3$

In particular,

$(x^{1/3}-x)(x^{2/3}+x^{4/3}+x^2)=x-x^3$
$(x^{1/2}-x)(x^{1/2}+x)=x-x^2$

so we have

$\displaystyle\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}\cdot\frac{x^{2/3}+x^{4/3}+x^2}{x^{2/3}+x^{4/3}+x^2}\cdot\frac{x^{1/2}+x}{x^{1/2}+x}=\lim_{x\to1}\frac{x-x^3}{x-x^2}\cdot\frac{x^{1/2}+x}{x^{2/3}+x^{4/3}+x^2}$

For $x\neq0$ and $x\neq1$ , we can simplify the first term:

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So our limit becomes

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3 years ago

In the diagram, how many angles are alternate exterior angles with angle 5?

Natasha_Volkova [10]

Answer:

Angle 11 is the alternate exterior of angle 5 meaning there is only 1 angle that is alternate of angle 5.

Step-by-step explanation:

An exterior angle is an angle outside of the shape (hence ex meaning out). However, an ALTERNATE angle is an angle opposite of a transversal line of another angle. The angles on the same transversal line of 5 are 8, 7, 9, 10, 12, and 11. However, we are looking for ALTERNATE EXTERIOR angles not just exterior. 8, 7, 9, 10, and 12 are just exterior which leaves angle 11 as alternate exterior. Angle 11 is the alternate exterior of angle 5 meaning there is only 1 angle that is alternate of angle 5.

4 0

3 years ago