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Mice21 [21]
3 years ago
12

coffee which normally sells for $2.19 per pound is now on sale for 5.49 for 3 lb how much is safe per pound by buying the three

pound can
Mathematics
1 answer:
N76 [4]3 years ago
3 0
What are the answer choices.??????????
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A square is a quadrilateral always sometimes never
lbvjy [14]
A quadrilateral is a shape with 4 sides, regardless of their lengths, angles, or symmetry. 

Therefore, a square is always a quadrilateral.
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3 years ago
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If A, B, and C are collinear, and AB = 18, AC = 41, what is a possible measure of BC?
ikadub [295]

Step-by-step explanation:

As ANC are collinear,

AB+BC=AC

so,

18+BC = 41

BC = 41-18

BC = 23 is the answer.

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Solve the linear system below using the substitution method. <br> y = 5x – 22<br> 3x +2y=34
insens350 [35]

Answer:

Use photo math, it will explain all the steps

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3 years ago
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My son has the following missing number pattern to solve.
melisa1 [442]
The only complete pattern is the middle one
we see that 38-29=9
so the middle number minus the first number equals the third number
for the last row
21-1=20  so you have 1  21   20
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17- ?=37
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6 0
3 years ago
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The equation of a circle is (x + 6)^2 + (y - 4)^2 = 16. The point (-6, 8) is on the circle.
pantera1 [17]

Answer:

y = 8 is the equation of tangent.

Step-by-step explanation:

The equation of the tangent to the circle at (-6,8) is of the form:

y = mx + c

where m is the slope of the tangent and c is the y-intercept.

The point (-6,8) lies on the circle and the tangent line as well.

Hence (-6,8) satisfies the line equation:

8 = m(-6) + c ⇒ c-6m = 8 -------------1

We know that slope of two perpendicular lines are related as:

m_{1}\times m_{2}=-1

At any point on the circle, the normal line at a point is always perpendicular to the tangent line at that point.

Hence :

m_{normal} \times m_{tangent}=-1

We can find the slope of the normal at point (-6,8) as it passes through the centre of the circle (-6,4) by using the two-points formula for slope.

m=\frac{y_2-y_1}{x_2-x_1}

         =\frac{8-4}{-6+6}

          = ∞

Slope of the normal is infinity and hence slope of tangent is -1/∞ = 0

Hence m=0

Putting m=0 in equation 1 we get:

c = 8

The equation of tangent line at (-6,8) is:

y = 8

6 0
3 years ago
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