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attashe74 [19]
3 years ago
7

A plane slices diagonally through a rectangular prism as shown. Which term best describes the cross-section formed by the inters

ection of the plane and the prism?

Mathematics
2 answers:
Iteru [2.4K]3 years ago
8 0

Answer:

B

Step-by-step explanation:

joja [24]3 years ago
3 0

Answer:

Rectangle shaped cross section is formed by intersection of plane and prism.

Step-by-step explanation:

Given: A rectangular Prism.

To find: Shape of Cross Section when a plane intersect the prism diagonally

A plane intersect the Rectangular prism .i.e, Cuboid diagonally which means plane passes from top edge of cuboid to edge on bottom on opposite side.

Figure is attached.

In this way we get a Rectangular shaped Cross section which includes edges of cuboid and diagonals of the side faces.

Therefore, Rectangle shaped cross section is formed by intersection of plane and prism.

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What is the absolute value of -3? <br> A. -3<br> B. 3
Leona [35]

Answer:

<h2>B. 3</h2>

Step-by-step explanation:

|a|=\left\{\begin{array}{ccc}a&if&a\geq0\\-a&if&a

Examples:

|3|=3\ because\ 3\geq0\\\\|-10|=-(-10)=10\ because\ -10

Your question:

|-3|=-(-3)=3\\\\|-3|=3

5 0
3 years ago
Help lease this is due tomorrow. help! ​
____ [38]

Answer:

p(2)= 2(13-P)                  

p(2)= 2(13-2)                  

p(2)=2(11)                        

p(2)= 22

p(3)= 2(13-p)

p(3)= 2(13-3)

p(3)= 2(10)

p(3)= 20

p(4)= 2(13-p)

p(4)= 2(13-4)

p(4)= 2(9)

p(4)= 18

v(4)w(2)= 3v+w

v(4)w(2)= 3(4) + 2

v(4)w(2)= 12+2

v(4)w(2)= 14

v(6)w(3)= 3v+w

v(6)w(3)= 3(6)+3

v(6)w(3)= 18+3

v(6)w(3)= 21

v(8)w(4)= 3v+w

v(8)w(4)= 3(8)+4

v(8)w(4)= 24+4

v(8)w(4)= 28

7 0
3 years ago
Which angle is in standard position
Readme [11.4K]

Answer:

The bottom one

Step-by-step explanation:

its vertex is located at the origin and one ray is on the positive x-axis

4 0
3 years ago
Read 2 more answers
Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8
Delvig [45]
We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34
Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86

Thus the 98% confidence interval will be (105.34, 141.86)


Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.
3 0
4 years ago
10/7=x/5 which of the following equation can be used to solve for the value of X?
V125BC [204]

Answer:

10*5 = 7x

Step-by-step explanation:

We can solve using cross products

10*5 = 7x

50 = 7x

divide each side by 7

50/7 =7x/7

50/7 =x

5 0
3 years ago
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