SOMEONE HELP PLZ ASAP!!!!!

I have no idea how to do this, please help!

Marta_Voda [28]

Answer:

24

Step-by-step explanation:

7 0

3 years ago

The sum of two numbers is 20. One number is one less than twice the second number. What are the two numbers?

murzikaleks [220]

Answer: Hope this helps.

13, 7

Step-by-step explanation:

Number one is 13

Number two is 7

Well 7 x 2 = 14, 14-1 = 7, and 7+13 = 20 making the answers true.

I figured out this number by eliminating numbers, I started with 5, ended with 8 to make a range of the possible numbers. Since 5 was too low and 8 was too high I knew the number had to be either 6 or 7, so I did 7 and I got the answer.

7 0

2 years ago

Read 2 more answers

Al simplificar la fraccion 150/600 a su mínima expresión se obtiene 15/6

zaharov [31]

Answer:

cierto

Step-by-step explanation:

8 0

3 years ago

In a specific video game scenario, you are given 1,000 gold. You can either train marines to defend your base at 50 gold a piece

Sloan [31]

Answer:

The system is:

$50m+200u\leq 1,000$

$u\leq 3$

$u\geq 0$

$m\geq 10$

Step-by-step explanation:

The variables of your equations are:

$m=\text{number of marines}$

$u=\text{number of upgrades}$

The constraints, which become inequalities are:

1. The total cost cannot be greater than 1,000 gold

Cost of training m number of marines at 50 gold a piece:

$50m$

Cost of purchasing u number of research weapon upgrades at 200 gold per upgrade:

$200u$

Total cost:

$50m+200u$

The cost is limited to 1,000 gold that you are given:

$50m+200u\leq 1,000$

That is the first inequality of your system

2. The game allows a maximum of three upgrades:

This sets an upper bound for the variable:

$u\leq 3$

Add the reasonable constraint that the number of upgrades cannot no be negative:

$u\geq 0$

3. You know that you need at least ten marines trained to survive

This sets a lower bound for the variable:

$m\geq 10$

And those are all the four inequalities that form your system to describe the number of marines and the number of upgrades you can train/purchae in the game:

$50m+200u\leq 1,000$

$u\leq 3$

$u\geq 0$

$m\geq 10$

3 0

3 years ago

Can anyone help me with this. It asks to solve and check your answer.

tankabanditka [31]

$\sf 4m-21=3(5m-1)$

First, distribute 3 into the parenthesis(multiply it to every term inside):

$\sf 4m-21=15m-3$

Add 21 to both sides:

$\sf 4m=15m+18$

Subtract 15m to both sides:

$\sf -11m=18$

Divide -11 to both sides:

$\sf m=-\dfrac{18}{11}$

To check our work we can plug this back into the original equation for 'm':

$\sf 4m-21=3(5m-1)$

$\sf 4(-\dfrac{18}{11})-21=3(5(-\dfrac{18}{11})-1)$

Multiply:

$\sf -\dfrac{72}{11}-21=3(-\dfrac{90}{11}-1)$

Distribute 3 into the parenthesis:

$\sf -\dfrac{72}{11}-21=-\dfrac{270}{11}-3$

Subtract:

$\sf -\dfrac{303}{11}=-\dfrac{303}{11}~\checkmark$

Both sides are equal to each other, so we solved it correctly.

6 0

3 years ago