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3 years ago

What is the sum of the geometric series 20 + 21 + 22 + 23 + 23 + 24 + … + 29?

Mathematics

2 answers:

Oxana [17]3 years ago

8 0

Answer:

1023

Step-by-step explanation:

2^0+2^1+2^2+2^3+2^4+2^5+2^6+2^7+2^8+2^9

1+2+8+16+32+64+128+256+512=1023

ikadub [295]3 years ago

3 0

<span>ok so i have recently discovered An easy way to find the sum is to simply add all the numbers together since there aren't that many of them.

so try to work it out ,ur smart,ur on brainly

</span>

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Need Answer Fast Please to solve the Linear Expression: 5(5n+2)+(3-2n)

tatyana61 [14]

Answer:

23n +13

Step-by-step explanation:

5(5n+2)+(3-2n)

Distribute

25n + 10 +3 -2n

Combine like terms

25n -2n + 10+3

23n +13

3 0

3 years ago

Read 2 more answers

Fill the table using this function rule.

ElenaW [278]

Y=29-2(1)
y=29-2=27
(1,27)
y=29-2(3)
y=29-6=23
(3,23)
y=29-2(4)
y=29-8=21
(4,21)
y=29-2(5)
y=29-10=19
(5,19)

7 0

3 years ago

Let F⃗ =2(x+y)i⃗ +8sin(y)j⃗ .

Alik [6]

Answer:

-42

Step-by-step explanation:

The objective is to find the line integral of $F$ around the perimeter of the rectangle with corners (4,0), (4,3), (−3,3), (−3,0), traversed in that order.

We will use <em>the Green's Theorem </em>to evaluate this integral. The rectangle is presented below.

We have that

$F(x,y) = 2(x+y)i + 8j \sin y = \langle 2(x+y), 8\sin y \rangle$

Therefore,

$P(x,y) = 2(x+y) \quad \wedge \quad Q(x,y) = 8\sin y$

Let's calculate the needed partial derivatives.

$P_y = \frac{\partial P}{\partial y} (x,y) = (2(x+y))'_y = 2\\Q_x =\frac{\partial Q}{\partial x} (x,y) = (8\sin y)'_x = 0$

Thus,

$Q_x -P_y = 0 -2 = - 2$

Now, by the Green's theorem, we have

$\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA = \int \limits_{-3}^{4} \int \limits_{0}^{3} (-2)\,dy\, dx \\ \\\phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-2y) \Big|_{0}^{3} \; dx\\ \phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-6)\; dx = -6x \Big|_{-3}^{4} = -42$