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Svet_ta [14]
3 years ago
5

A metalworker has a metal alloy that is 15​% copper and another alloy that is 60​% copper. How many kilograms of each alloy shou

ld the metalworker combine to create 90 kg of a 51​% copper​ alloy?
Mathematics
1 answer:
coldgirl [10]3 years ago
6 0

18 kg of 15% copper and 72 kg of 60% copper should be combined by the metalworker to create 90 kg of 51% copper alloy.

<u>Step-by-step explanation:</u>

Let x = kg of 15% copper alloy

Let y = kg of 60% copper alloy

Since we need to create 90 kg of alloy we know:

x + y = 90

51% of 90 kg = 45.9 kg of copper

So we're interested in creating 45.9 kg of copper

We need some amount of 15% copper and some amount of 60% copper to create 45.9 kg of copper:

0.15x + 0.60y = 45.9

but

x + y = 90

x= 90 - y

substituting that value in for x

0.15(90 - y) + 0.60y = 45.9

13.5 - 0.15y + 0.60y = 45.9

0.45y = 32.4

y = 72

Substituting this y value to solve for x gives:

x + y = 90

x= 90-72

x=18

Therefore, in order to create 90kg of 51% alloy, we'd need 18 kg of 15% copper and 72 kg of 60% copper.

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Step-by-step explanation:

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Below in bold.

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The sum of a 3 digit number and a 1 digit number is 217. The product of the numbers is 642. If one number is between 200 and 225
algol [13]
Let, the numbers be "x" and "y". Consider "x" as the triple digit number.
Now, according to the question,
x + y = 217..........................equation (1)

x * y = 642............................equation (2)

Now,
Taking equation (2),
x * y = 642
y = 642 / x..................................equation (3)

Now, Taking equation (1),
x+y=217

Substituting the value of y from equation (3), we get,

x+ \frac{642}{x} =217

\frac{x *x+642}{x} =217

x^{2} +642 =217*x

x^{2} +642 =217x

x^{2} +642-217x =0

x^{2} -217x+642 =0

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Using zero product property,
EITHER,
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Since, "x" is the triple digit number, x = 214.
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Substituting the value of "x" in the equation, we get,
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So, the numbers are 214 and 3.



5 0
3 years ago
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Answer:

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Or X = 420ml

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6 0
2 years ago
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