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posledela
3 years ago
10

A debate competition has participants from three different schools: 15 from James Elementary, 18 from George Washington Universi

ty, and 12 from the MLK Jr. Academy. All teams must have the same number of students. Each team can have only students from the same school. How many students can be on each team?
Mathematics
2 answers:
meriva3 years ago
7 0

Answer:

The number of students in each team can be : 3

Step-by-step explanation:

Since we have to form teams such that two conditions must be satisfied:

  • All teams must have equal number of students.
  • Each team can have only student from the same school.

Now on the basis of the above conditions to be satisfied we see that we can form <em>"12 teams"</em> such that each team must have <em>"three students"</em> from three different schools.

Hence, the number of students each team could have is 3.

Crazy boy [7]3 years ago
4 0
Is the answer not 12?

If their only limitation is that they need equal numbers then it they can have 12.

Even though JE and GWU and more then 12 students they arent allowed to swap so the maximum that MLK Jr can have is only ever going to be 12
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A student was asked to identify the following numbers as rational or irrational. Determine if the student has made any mistakes.
ioda

Answer:

Yes they are wrong, rational & irrational ones down below.

Step-by-step explanation:

So, lets start this by asking, what is a rational and irrational number?

Rational numbers are literally any numbers that arent pi, e, or other symbols, as well as square roots.

Irrational numbers are exactly the opposite, being the numbers that are symbols, including square roots.

Note that the symbols listed above such as pi are values that are neverending.

Now, using what we know of rational and irrational numbers, let see which answers are rational and which are not.

So, we start off with:

-13/3

I do not see a square root.

I do not see a symbol such as pi either.

It is not a ever going number.(number that continues infinitly)

<u>So -13/3 is a rational number.</u>

Next we have \sqrt{37}

immediatly we tell it has a square root.

<u>So </u>\sqrt{37}<u> is a irrational number.</u>

Next we have 0.1234

This is not a every going number.

There isnt a square root.

And it isnt a symbol.

<u>So 0.1234 is a rational number.</u>

Next we have -\sqrt{100}

Again, we can immediatly know it has a square root.

<u>So  </u>-\sqrt{100}<u> is a irrational number.</u>

Next we have -77

This is not every going.

It doesnt have a square root.

It doesnt have a symbol.

So -77 is a rational number.

Lastly we have   -\sqrt{12}

Like the other ones, we can imediatly tell it has a square root.

<u>So </u>-\sqrt{12}<u> is a irrational number.</u>

Bascially, to answer further questions, here is the criteria for a number being rational:

  • It <u>does not</u> have a square root.
  • It <u>does not </u>have a symbol.
  • It<u> is not </u>a infinitly going on number.

If one of these criterias are not met, then you know its a irrational number.

Hope this helps! :D

6 0
3 years ago
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