All categories

2 years ago

The product of (x-7)^2

Mathematics

1 answer:

Nimfa-mama [501]2 years ago

6 0

Answer:

x^2 - 14x + 49

Step-by-step explanation:

(x - 7)(x - 7) = x^2 -7x - 7x + (7)(7)

You might be interested in

The graph of the function f(x) = (x - 4)(x + 1) is shown

Ostrovityanka [42]

What are the statements?

4 0

2 years ago

Will give brainliest!!

yawa3891 [41]

Answer:

$r=\frac{9\cos \theta}{\sin^2 \theta}$

Step-by-step explanation:

The given equation in rectangular coordinates is;

$y^2=9x$

We use the relation;

$x=r\cos \theta$

and

$y=r \sin \theta$

This implies that;

$(r \sin \theta)^2=9(r \cos \theta)$

$r^2 \sin^2 \theta=9r \cos \theta$

Divide through by r to get;

$r \sin^2 \theta=9\cos \theta$

Divide both sides by $\sin^2 \theta$

$r=\frac{9\cos \theta}{\sin^2 \theta}$

8 0

2 years ago

Number 6 part a & b Number 7 Please & thank you

miv72 [106K]

Answer:

6- Part A: $750a+1200r=1000000$

Part B: $1065a+876r=1000000$

Solution of the system: $a\approx521.739\;\;\;\;b\approx507.246$

Step-by-step explanation:

Part A:

In words, the equation is formed like this:

Total kg of Arabica + Total kg of Robusta = Total kg of coffee

Now, the total of each yield is calculated by the product of kg/hectare and number of hectares. Thus, the equation is:

$750a+1200r=1000000$

Part B:

In words:

Arabica's worth + Robusta's worth = plantation worth

Each yield's worth is given by the product of the price per kg and the corresponding production. So, the equation is:

$1.42(750a)+0.73(1200r)=1000000\\1065a+876r=1000000$

3 0

2 years ago

Factor completely 4(x+1)^2/3 + 12(x+1)^-1/3

wolverine [178]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
\left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}
\\\\
-------------------------------\\\\
%4(x+1)^2/3 + 12(x+1)^-1/3
4(x+1)^{\frac{2}{3}}+12(x+1)^{-\frac{1}{3}}\implies 4(x+1)^{\frac{2}{3}}+12\cfrac{1}{(x+1)^{\frac{1}{3}}}
\\\\\\$

$\bf 4(x+1)^{\frac{2}{3}}+\cfrac{12}{(x+1)^{\frac{1}{3}}}\impliedby \textit{so, our LCD is }(x+1)^{\frac{1}{3}}
\\\\\\
\cfrac{4(x+1)^{\frac{2}{3}}\cdot (x+1)^{\frac{1}{3}}+12}{(x+1)^{\frac{1}{3}}}\implies \cfrac{4(x+1)^{\frac{2}{3}+\frac{1}{3}}+12}{(x+1)^{\frac{1}{3}}}
\\\\\\
\cfrac{4(x+1)^{\frac{3}{3}}+12}{(x+1)^{\frac{1}{3}}}\implies \cfrac{4(x+1)+12}{(x+1)^{\frac{1}{3}}}\implies \cfrac{4x+4+12}{(x+1)^{\frac{1}{3}}}
\\\\\\
\cfrac{4x+16}{(x+1)^{\frac{1}{3}}}\implies \cfrac{4(x+4)}{\sqrt[3]{x+1}}$

3 0

2 years ago

Read 2 more answers

Which value in the replacement set is a solution to this equation? 2n + 5 = 27 Replacement set: {11, 12, 13} Drag the solution i

Alchen [17]

11 is the answer to your question.

2×11=22

22+5=27

6 0

2 years ago