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podryga [215]
4 years ago
5

Solving Rational equations. LCD method. Show work. Image attached.

Mathematics
1 answer:
kenny6666 [7]4 years ago
6 0

Answer:

m=-\frac{3}{2}

Step-by-step explanation:

The given equation is

\frac{m}{m+1}+\frac{5}{m-1}=1

The Least Common Denominator is (m-1)(m+1).

We multiply through by the LCD to get;

(m-1)(m+1)\times \frac{m}{m+1}+(m-1)(m+1)\times\frac{5}{m-1}=(m-1)(m+1)\times1

Simplify

(m-1)\times \frac{m}{1}+(1)(m+1)\times\frac{5}{1}=(m-1)(m+1)\times1

m(m-1)+5(m+1)=(m-1)(m+1)

Expand;(Use difference of two squares on the right hand side)

m^2-m+5m+5=m^2-1

Group similar terms;

m^2-m^2-m+5m=-1-5

Simplify;

4m=-6

Divide through by 4.

m=\frac{-6}{4}

m=-\frac{3}{2}

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4[( 8 + 4)10] + 24 devided by 2^3
Nikolay [14]
4[(8+4)10] + 24
so 8 + 4 is 12. Multiply that by 10 and that's 120.
120 + 24 is 144
144 × 4 is 576
for "devided by 2^3" do you mean divided by 2/3?
If so then its 576 ÷ 2/3 = 96
8 0
4 years ago
A code consists of two digit numbers chosen from 00-99 (i.E 00, 01, 02…..99) followed by two different letters of the alphabet.
Ede4ka [16]

Answer: 1/67600

Step-by-step explanation:

probability that the code is 43MZ:

Probability = (Total Required outcome / total possible outcomes)

Possible outcomes (digit) = (00,.............. ..., 99)

2.) possible outcomes (alphabet) = (A, B,............... .., Z)

P(43MZ) = P(43) × P(M) × P(Z)

P(43) = 1/100

P(M) = 1/26

P(Z) = 1/26

THEREFORE ;

P(43MZ) = (1/100) × (1/26) × (1/26) = 1/67600

4 0
4 years ago
mary wants to put a fence around her garden. the garden measures 10 ft by 6ft. if fencing costs $5,how much will the fence cost
SVETLANKA909090 [29]
The total cost of the fence would be 132$.


7 0
3 years ago
For each of the figures write an absolute value equation to satisfy the given solution set
Lubov Fominskaja [6]
Answer is: I x-11 I = 6
3 0
3 years ago
Read 2 more answers
Thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally
sasho [114]

Answer:

a) P(X

P(z

b) P(X>7.0)=P(\frac{X-\mu}{\sigma}>\frac{7-\mu}{\sigma})=P(Z1.47)

P(z>1.47)=1-P(z

c)  P(3

P(-0.882

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the thickness of a population, and for this case we know the distribution for X is given by:

X \sim N(4.5,1.7)  

Where \mu=4.5 and \sigma=1.7

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using excel or the normal standard table:

P(z

Part b

We are interested on this probability

P(X>3.0)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>7.0)=P(\frac{X-\mu}{\sigma}>\frac{7-\mu}{\sigma})=P(Z1.47)

And we can find this probability using excel or the normal standard table:

P(z>1.47)=1-P(z

Part c

P(3

And we can find this probability using excel or the normal standard table liek this:

P(-0.882

3 0
3 years ago
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