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Tomtit [17]
3 years ago
12

What happens to the value of the expression 1+3f1+3f1, plus, 3, f as fff increases? Choose 1 answer: Choose 1 answer: (Choice A)

A It increases. (Choice B) B It decreases. (Choice C) C It stays the same.
Mathematics
2 answers:
Leto [7]3 years ago
7 0

Answer:

A. It Increases

Step-by-step explanation:

Given the expression:

1+3f

When f=1, 1+3f=1+3(1)=1+3=4

When f=2, 1+3f=1+3(2)=1+6=7

When f=3, 1+3f=1+3(3)=1+9=10

We can see that the value of the given expression for each successive term increases and in fact form the sequence

4,7,10,...

Therefore, when f increases, 1+3f increases.

sdas [7]3 years ago
6 0

Answer:

it increases

Step-by-step explanation:

your welcome!!!! :)

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Read 2 more answers
Given the position of the particle, what the position(s) of the particle when it’s at rest
choli [55]

The position function of a particle is given by:

X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t

The velocity function is the derivative of the position:

\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}

The particle will be at rest when the velocity is 0, thus we solve the equation:

2t^2-9t-18=0

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Substituting:

\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}

We have two possible answers:

\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

undefined

6 0
1 year ago
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