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3 years ago

How can you use a formula for one measurement to write a formula for a different measurement?

Mathematics

1 answer:

Dmitrij [34]3 years ago

3 0

Answer:

Write the formula for one measurement, then solve the formula for the different measurement you want to find and use this new formula to find that measurement.

Step-by-step explanation:

We can understand this through an example.

If we need to find the lenght of a rectangle whose width is 4 feet and whose perimeter is 28 feet, we can use a formula for one measurement to write a formula for a different measurement:

- We need to write the formula for the perimeter of a rectangle:

$P=2l+2w$

Where "l" is the lenght and "w" is the width.

- Since we know the width and the perimeter of the rectangle and we need to find the lenght, we can solve for "l":

$P=2l+2w\\\\P-2w=2l\\\\l=\frac{P-2w}{2}$

Now we get a new formula for calculate a differente measurement (the lenght of the rectangle).

- Substituting values, we get:

$l=\frac{28ft-2(4ft)}{2}=10\ ft$

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2 years ago

13 + 5x - 4y - 8 . I need to simplify the expression

IrinaK [193]

Answer:

5+5x-4y

Step-by-step explanation:

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2 years ago

Which table represents the graph of a logarithmic function in the form y=log3x when b>1?

alex41 [277]

Answer:

The satisfied table of the given function $y = log_{b} (x)$

x 1/8 1/4 1/2 1 2

y -3 -2 -1 0 1

Step-by-step explanation:

Explanation :-

Given logarithmic function $y = log_{b} (x)$ if b >1

Given first table

put x = $\frac{1}{8}$ given b > 1 so we can choose b = 2

$y = log_{2} (\frac{1}{8} )$

$y = log_{2} (2^{-3} )$

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-3} ) = -3 log_{2} (2) = -3 (1) = -3$

y = -3

ii)

put x = $\frac{1}{4}$ given b > 1 so we can choose b = 2

$y = log_{2} (\frac{1}{4} )$

$y = log_{2} (2^{-2} )$

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-2} ) = -2 log_{2} (2) = -2 (1) = -2$

y = -2

iii)

put x = $\frac{1}{2}$ given b > 1 so we can choose b = 2

$y = log_{2} (\frac{1}{2} )$

$y = log_{2} (2^{-1} )$

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-1} ) = -1 log_{2} (2) = - (1) = -1$

y = -1

iv)

put x = 1 given b > 1 so we can choose b = 2

$y = log_{2} (1 )$ = 0

y = 0

v)

put x = $2$ given b > 1 so we can choose b = 2

$y = log_{2} (2 )$

y = 1

Final answer:-

The satisfied table of the given function

x 1/8 1/4 1/2 1 2

y -3 -2 -1 0 1

8 0

3 years ago

Read 2 more answers

s quadrilateral JKLM the result of a dilation of quadrilateral ABCD by a scale factor of 2? Why or why not?

Likurg_2 [28]

If quadrilateral JKLM has given values, as well as quadrilateral ABCD, it can be concluded from the given values if JKLM is a result of a dilation of ABCD by a scale factor of 2. Dilation factor is used to scale up a given figure. If ABCD has measurements of 1, 2, 3, and 4. Then the measurements of JKLM should be 4, 8, 12, and 16.

4 0

3 years ago

Find the absolute value -5/6|

Nadya [2.5K]

Answer:

5/6 OR 0.83 (with the three repeating)

Hope that helps!

Step-by-step explanation:

5 0

3 years ago