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Marina CMI [18]
3 years ago
13

How can you use a formula for one measurement to write a formula for a different measurement?

Mathematics
1 answer:
Dmitrij [34]3 years ago
3 0

Answer:

Write the formula for one measurement, then solve the formula for the different measurement you want to find and use this new formula to find that measurement.

Step-by-step explanation:

 We can understand this through an example.

If we need to find the lenght of a rectangle whose width is 4 feet and whose perimeter is 28 feet, we can use a formula for one measurement to write a formula for a different measurement:

 - We need to write the formula for the perimeter of a rectangle:

P=2l+2w

Where "l" is the lenght and "w" is the width.

- Since we know the width and the perimeter of the rectangle and we need to find the lenght, we can solve for "l":

P=2l+2w\\\\P-2w=2l\\\\l=\frac{P-2w}{2}

Now we get a new formula for calculate a differente measurement (the lenght of the rectangle).

- Substituting values, we get:

l=\frac{28ft-2(4ft)}{2}=10\ ft

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50 POINTS IF ANSWERED CORRECT(Score for Question 3 of 5 points) 3. Given this equation: 2.5x+6=3.25x+3 (a) Write a real-world pr
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below

Step-by-step explanation:

Two students are selling cookies at a bake fair. Jake is selling cookies for $2.50 each plus $6 for the packaging. Kevin is selling cookies for $3.25 each plus $3 for the packaging. How ma cookies would both have to sell to make the same amount of money?

2.5x + 6 = 3.25x + 3

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Sixteen percent of videos are shorter than what
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189 seconds

Step-by-step explanation:

16% shorter,

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The phone company Splint has a monthly cellular plan where a customer pays a flat fee for unlimited voice calls and then a certa
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Step-by-step explanation:

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2 years ago
A number is selected from the set {1, 2, 3, 5, 15, 21, 29, 38, 500}. If equal elemental probabilities are assigned, what is the
Zanzabum

Answer:

The required probability is \frac{7}{9}.

Step-by-step explanation:

Set given is:

S = {1, 2, 3, 5, 15, 21, 29, 38, 500}

Total number of elements in set, n(S) = 9

Let A be the event that the number is less than 29 ({1, 2, 3, 5, 15, 21}).

Number of items in the event A, n(A) = 6

Probability of event A,

P(A) = \dfrac{n(A)}{n(S)}}=\dfrac{6}{9} \Rightarrow \dfrac{2}{3}

Formula for probability of any event E:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

Let B be the event that the number is odd (either of {1,3,5,15,21,29}).

Number of items in the event B, n(B) = 6

Probability of event B,

P(B) = \dfrac{n(B)}{n(S)}}=\dfrac{6}{9} \Rightarrow \dfrac{2}{3}

The event A and B have a few elements in common, i.e. numbers less than 29 which are odd as well.

The common elements are represented as:

A \cap B = \{1, 3, 5, 15, 21\}

n(A\cap B) = 5

P(A \cap B ) = \dfrac{n(A \cap B)}{n(s)}\\\Rightarrow P(A \cap B) = \dfrac{5}{9}

To find probability of selecting a number which is either less than 29 (event A) or odd (event B),

We have to find P(A\ or \ B) which is represented as P(A \cup B) and the formula is:

P(A \cup B) = P(A) + P(B) - P(A \cap B)\\\Rightarrow \dfrac{2}{3} + \dfrac{2}{3} - \dfrac{5}{9}\\\Rightarrow \dfrac{12-5}{9}\\\Rightarrow \dfrac{7}{9}

The required probability is \frac{7}{9}.

7 0
3 years ago
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