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Ksenya-84 [330]

3 years ago

10

If x+3y=-2 and 2x-6y=-8, which of the following equation is true?

1 answer:

rjkz [21]3 years ago

3 0

Your answer is B) 12y = 4

You can find this by first rearranging the equation x + 3y = -2 to the form ‘x =‘:
x = -2 - 3y.

Then you can substitute this into the second equation, 2x - 6y = -8, and expand and solve:
2(-2 - 3y) - 6y = -8
-4 - 6y - 6y = -8
-12y = -4

Now because we know that -12y = -4, this is equivalent to 12y = 4, which is option B.

I hope this helps! Let me know if you have any questions :)

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0.8 as a fraction in simplest form

Tju [1.3M]

The answer would be 4 over 5 or 4/5

7 0

3 years ago

Read 2 more answers

ryzh [129]

Answer:

D. y = 3(1/3)x

Step-by-step explanation:

if x = -1

y = 9

A. y = (1/3) -¹ = 3 X

B. y = (1/3) -¹ + 2 = 5 X

C. y = (1/3) -¹ + 3 X

D. y = 3(1/3) -¹ = 9 ✓

So D is the answer

<em>H</em><em>O</em><em>P</em><em>E</em><em> </em><em>T</em><em>H</em><em>I</em><em>S</em><em> </em><em>H</em><em>E</em><em>L</em><em>P</em><em>S</em><em> </em><em>A</em><em>N</em><em>D</em><em> </em><em>H</em><em>A</em><em>V</em><em>E</em><em> </em><em>A</em><em> </em><em>N</em><em>I</em><em>C</em><em>E</em><em> </em><em>D</em><em>A</em><em>Y</em><em> </em><em><</em><em>3</em>

3 0

2 years ago

Can some one give me the answers to the slope questions please ?!

viktelen [127]

Answer:

I gotchu homie:

1. Slope = 5

2. Slope = 2/3

3. Slope = 3/4

4. Slope = 5/2

If you want to understand how to find them feel free to ask :)

4 0

3 years ago

Please solve the following sum or difference identity.

xxTIMURxx [149]

Answer:

$sin(A - B) = \frac{4}{5}$

Step-by-step explanation:

Given:

$sin(A) = \frac{24}{25}$

$sin(B) = -\frac{4}{5}$

Need:

$sin(A - B)$

First, let's look at the identities:

sum: $sin(A + B) = sinAcosB + cosAsinB$

difference: $sin(A - B) = sinAcosB - cosAsinB$

The question asks to find sin(A - B); therefore, we need to use the difference identity.

Based on the given information (value and quadrant), we can draw reference triangles to find the simplified values of A and B.

sin(A) = $\frac{24}{25}$

cos(A) = $\frac{7}{25}$

sin(B) = $-\frac{4}{5}$

cos(B) = $\frac{3}{5}$

Plug these values into the difference identity formula.

$sin(A - B) = sinAcosB - cosAsinB$

$sin(A - B) = (\frac{24}{25})(\frac{3}{5}) - (-\frac{4}{5})(\frac{7}{25})$

Multiply.

$sin(A - B) = (\frac{72}{125}) + (\frac{28}{125})$

Add.

$sin(A - B) = \frac{4}{5}$

This is your answer.

Hope this helps!

6 0

3 years ago

Read 2 more answers

Help please :) I'd greatly appreciate it

azamat

= 4i (2i) <span>√6
= 8i^2 </span><span>√6 but i^2 = -1
= - 8</span><span>√6</span><span>

</span>

6 0

3 years ago