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3 years ago

I have no idea how to do this problem I need help

Mathematics

2 answers:

Anettt [7]3 years ago

5 0

Answer:

PEMDAS

Step-by-step explanation:

zaharov [31]3 years ago

5 0

You would do BPEMDAS brackets pretenses exponents multiplication or division (whichever comes first) and then subtraction or addiction (which ever comes first)

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A test is worth 100 points where each multiple choice question is worth 2 points and each short answer question is worth 6 point

xeze [42]

10 Short answers and 20 multiple choice. Hope this helps. :)

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4 years ago

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damaskus [11]

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3 years ago

You must be at least 42 inches tall to ride the bumper cars at an amusement park. Write an inequality that represents this situa

Finger [1]

$x \geqslant 42$

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3 years ago

X ^ (2) y '' - 7xy '+ 16y = 0, y1 = x ^ 4

nignag [31]

Standard reduction of order procedure: suppose there is a second solution of the form $y_2(x)=v(x)y_1(x)$ , which has derivatives

$y_2=vx^4$
${y_2}'=v'x^4+4vx^3$
${y_2}''=v''x^4+8v'x^3+12vx^2$

Substitute these terms into the ODE:

$x^2(v''x^4+8v'x^3+12vx^2)-7x(v'x^4+4vx^3)+16vx^4=0$
$v''x^6+8v'x^5+12vx^4-7v'x^5-28vx^4+16vx^4=0$
$v''x^6+v'x^5=0$

and replacing $v'=w$ , we have an ODE linear in $w$ :

$w'x^6+wx^5=0$

Divide both sides by $x^5$ , giving

$w'x+w=0$

and noting that the left hand side is a derivative of a product, namely

$\dfrac{\mathrm d}{\mathrm dx}[wx]=0$

we can then integrate both sides to obtain

$wx=C_1$
$w=\dfrac{C_1}x$

Solve for $v$ :

$v'=\dfrac{C_1}x$
$v=C_1\ln|x|+C_2$

Now

$y=C_1x^4\ln|x|+C_2x^4$

where the second term is already accounted for by $y_1$ , which means $y_2=x^4\ln x$ , and the above is the general solution for the ODE.

4 0

3 years ago

Help urgent In a class of 35 students 15 of them have cats 16 have dogs 3 hangs none how many probability does have both

dalvyx [7]

Answer:

9/25

Step-by-step explanation:

Number of student who has cat , dog = 25 - 3 = 22

Number of students who has cat and dogs = (15 + 16) - 22

= 31 - 22 = 9

Number of students who has only cats = 15 - 9 = 6

Number of students who has only dogs = 16 - 9 = 7

P(Cat & dog) = 9/25

8 0

3 years ago