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Gelneren [198K]
3 years ago
7

Elena and Matthew are president and vice-president of their ninth-grade class at Riverside High School. They have suggested that

the school sponsor a dance to raise money for the victims of a recent hurricane. The expenses for the dance will be $250 for the DJ and $100 for the refreshments. Tickets will cost $5 a person. How many tickets must be sold in order to raise $1,000 after expenses?
I need the right answer
A.250
B.270
C.350
D.420
Mathematics
2 answers:
Korolek [52]3 years ago
5 0
Answer:
B. 270 

250 + 100 + 1,000 = after expenses
5x = 1,350           divide by 5
  x = 270
dimulka [17.4K]3 years ago
4 0

250 + 100 = 350

350 + 1000 = 1350

1350 / 5 = 270

they need to sell 270 tickets

 answer is B

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If the squared difference of the zeroes of the quadratic polynomial x2+kx+30 is equal to 169 find the value of k and the zeroes
anyanavicka [17]

ANSWER

x  =  2 \: \: or \:  \:  x  =  15

Or

x  =   - 2 \: \: or \:  \:  x  =   -  15

EXPLANATION

The given polynomial is

f(x) = {x}^{2}  + kx + 30

where a=1,b=k, c=30

Let the zeroes of this polynomial be m and n.

Then the sum of roots is

m + n =  -  \frac{b}{a}  =  -k

and the product of roots is

mn =  \frac{c}{a}  = 30

The square difference of the zeroes is given by the expression.

( {m - n})^{2} =  {(m + n)}^{2} - 4mn

From the question, this difference is 169.

This implies that:

( { - k)}^{2}  - 4(30) = 169

{  k}^{2}  -120= 169

k^{2} = 289

k=  \pm \sqrt{289}

k=  \pm17

We substitute the values of k into the equation and solve for x.

f(x) = {x}^{2}   \pm17x + 30

f(x) = (x  \pm2)(x  \pm 15)

The zeroes are given by;

(x  \pm2)(x  \pm 15) = 0

x  =  \pm2 \: \: or \:  \:  x  =  \pm 15

5 0
3 years ago
Anne is running on a trail at an average speed of 6 miles per hour beginning at mile marker 4. John is running on the trail at t
Sphinxa [80]

Answer:

John is running faster.

Step-by-step explanation:

Given that:

Average Speed of Anne = 6 miles per hour

Speed of John can be represented in the table below:

\begin{center}\begin{tabular}{ c c}Time (hours) x & Mile Marker y \\ 0 & 1  \\  0.5 & 4.5  \\   1 & 8  \\ 1.5 & 11.5  \\\end{tabular}\end{center}

To find:

Who is running faster of the both i.e. Anne and John?

Solution:

Here, to find the faster runner we can compare the average speed of both the runners.

We are given that, average speed of Anne = 6 miles per hour

We will have to calculate the average speed of John to find the faster runner.

<em>Average speed</em> can be calculated by dividing the total distance traveled with the total time taken.

Total distance traveled by John = 11.5 - 1 = 10.5 miles

Total time taken by John = 1.5 hours

Average speed of John = \frac{10.5}{1.5} = 7\ miles/hr

Clearly Average speed of John is greater than that of Anne's.

Therefore, <em>John runs faster</em>.

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