<span>a^3 - b^3 = (a - b) </span><span>(<span>a^2 + </span>ab + b^2)
</span><span>so
x^3 - 4^3 = (x - 4)(x^2 + 4x + 16)
hope it helps</span>
Answer:
-6x-42
Step-by-step explanation:
Open parenthesis.
-42-6x is what you get once opened.
We can find this integer using a system of equations. The first thing we look at is the first sentence.
Let's call X The first integer,
Let's call Y the second integer.
So, X+Y=61 and X-Y= 1
Using Substituion on the second equation, we get
X=Y+1
(Now we plug in Y+1 into the second equation for X)
So,
(Y+1)+Y=61
2Y=60
Y=30
So, one of the integers is 30.
Now to find the second, we go back to
X=Y+1
X=30+1
X=31.
So, the integers are 31 and 30.
Hope this helps!
A quadratic expression<span> is any mathematical </span>expression<span> whose power or degree is two. In other words, any </span>expression<span> that uses variables where the highest exponent or the </span>expression's<span> degree is two is a </span>quadratic expression<span>. The </span>expression<span> must have a power of two, no higher nor lower.</span>
<span>Based on the data in the two-way table, the probability of being older than 25 years and having a hemoglobin level above 11 is
(154-69)/(429-139)
=85/290
=0.2931~0.29
Answer: A. 0.29
</span><span>The probability of having a hemoglobin level above 11 is
P(H>11)
=154/429
=0.35897~0.36
Answer: </span><span>C:0.36
</span><span>Being older than 25 years and having a hemoglobin level above 11
</span>Are not dependent on each other because w have not been told about any factors that were included in selection of sample.
Answer: <span>B.are not</span>
