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anastassius [24]
3 years ago
10

The legs of a right triangle are 18 centimeters and 80 centimeters long. What is the length of the hypotenuse

Mathematics
2 answers:
jeka57 [31]3 years ago
6 0
 The formula to find a hypotenuse is as follows:
a^2 + b^2 = c^2
Write out your triangle, labeling one part as 18, and another as 80. Connect a line between the end points of each line, and give a letter to a value. For my example, I will use 18 as a and 80 as b. 
18^2 + 80^2 = c^2
Solve this by squaring these numbers.
324 + 6400 = c^2
Add these numbers
6724 = c^2
 Then, finally, deprive the square root from 6724 and c^2
82 = c
 Since c is you hypotenuse, 82 centimeters is your answer. This checks out because your hypotenuse must be the largest number of the three, and if not, you did something wrong. However, this all checks out, meaning your hypotenuse is 82 centimeters. Hope this helped!
Brilliant_brown [7]3 years ago
4 0
a^2 + b^2 = c^2\\\\18^2 + 80^2 = c^2\\\\6724 = c^2\\\\c = \sqrt{6724}\\\\ c = 82

The hypotenuse is 82 centimeters long.
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Answer:

The probability of the number of starfish dropping below 3 is 0.0463.

Step-by-step explanation:

Let X represent the number of starfish in the tide pool.

X follows a Poisson distribution with mean 6.4.

The formula for Poisson distribution is as follows.

P(X=x) = e^{-6.4} * [6.4^{x} / x!] when x = 0, 1, ...

P(X = x) = 0 otherwise

We need to find the probability that the number of starfish in the tide pool drops below 3.

Therefore, the required probability is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X=2)

P(X < 3) = e^{-6.4} + (e^{-6.4}*6.4) + (e^{-6.4}*6.4^{2}/2)

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3 years ago
An automobile manufacturer is concerned about a possible recall of its best selling four-door sedan. If there was a recall there
goldfiish [28.3K]

Complete question is;

An automobile manufacturer is concerned about a possible recall of its best - selling four-door sedan. If there were a recall, there is a probability of 0.25 of a defect in the brake system, 0.18 of a defect in the transmission, 0.17 of a defect in the fuel system, and 0.40 of a defect in some other area.

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(b) What is the probability that there are no defects in either the brakes or the fueling system?

Answer:

A) 0.27

B) 0.73

Step-by-step explanation:

Let B denote that there is a defect in the break system

Let T demote that there is a defect in transmission

Let F denote that there is a defect in the fuel system.

Let P denote that there is a defect in some other area.

Now, we are given;

P(B) = 0.25

P(T) = 0.18

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A) We are given that probability of defects in both brakes and the fueling system simultaneously is 0.15.

Thus, it means; P(B ⋂ F) = 0.15

Now, we want to find the probability that the defect is the brakes or the fueling system. This is expressed as;

P(B ⋃ F) = P(B) + P(F) - P(B ⋂ F)

Plugging in the relevant values to give;

P(B ⋃ F) = 0.25 + 0.17 - 0.15

P(B ⋃ F) = 0.27

B) We want to find the probability that there are no defects in either the brakes or the fueling system.

This is expressed as;

P(B' ⋃ F') = 1 - P(B ⋃ F)

Plugging in relevant value;

P(B' ⋃ F') = 1 - 0.27

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Answer:

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