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erma4kov [3.2K]
2 years ago
5

Lindsay got her hair cut. The cost of a haircut

Mathematics
1 answer:
vodka [1.7K]2 years ago
8 0
16 x .20 add the .20 value for the total price
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.Divide the sum of 13/5 and -12/7 by the product of -31/7 and -(1/2)
andre [41]

Answer:

hello u so cool i admire you <3

6 0
2 years ago
Read 2 more answers
Factor completely 3x(x + 2) + 4(x + 2). (1 point) (x + 2)(7x)
Nezavi [6.7K]

ANSWER

(x + 2)(3x + 4)

EXPLANATION

The given expression is

3x(x + 2) + 4(x + 2)

We can see that (x+2) is the greatest common factor.

We factor to obtain;

(x + 2)( 3x + 4)

The correct choice is C.

6 0
3 years ago
25+12 1/2 + 61/4+31/8+19/16+25/32=
Len [333]
Make them all have the same denominator
32

25+12 16/32+488/32+124/32+38/32+25/32

Add all of the numerators... to get 691/32+1184/32
1875/32
Simplify to get 58 19/32
4 0
3 years ago
Solve the proportion. i need help.<br> x+3/6=8/3<br><br> x=?
stellarik [79]

Answer:

x = 2 1/6 (13/6)

Step-by-step explanation:

to solve the proportion you must first find the LCF or least common factor

that is 6

so turn 8/3 into 16/6 by multiplying it by 2/2

x + 3/6 = 16/6

then you subtract 3/6 from both sides

x = 13/6

x is 2 1/6

6 0
2 years ago
Read 2 more answers
QUESTION 1 The driving distance for the top 100 golfers on the PGA tour is between 284.7 and 310.6 yards.Assume that the driving
GarryVolchara [31]

Answer:

P(X>300)

And we can find this probability with the complement rule:

P(X>300)= 1-P(X

Step-by-step explanation:

For this case we define the random variable X ="driving distance for the top 100 golfers on the PGA tour" and we know that:

X \sim Unif (a=284.7, b=310.6)

And for this case the probability density function is given by:

f(x) =\frac{1}{310.6 -284.7} =0.0386 , 284.7 \leq X \leq 310.6

And the cumulative distribution function is given by:

F(x) =\frac{x-284.7}{310.6-284.7} , 284.7 \leq X \leq 310.6

And we want to find this probability:

P(X>300)

And we can find this probability with the complement rule:

P(X>300)= 1-P(X

6 0
3 years ago
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