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ivanzaharov [21]
3 years ago
11

Find the area of a regular hexagon with an apothem 17.3 miles long and a side 20 miles long

Mathematics
1 answer:
Zinaida [17]3 years ago
4 0
The area of a hexagon is \frac{3 \sqrt{3} }{2} a^{2} where a = one side

\frac{3 \sqrt{3} }{2} 20^{2}

\frac{3*200 \sqrt{3} }{2}

\frac{600 \sqrt{3} }{2}

300 \sqrt{3} ≈ 1038 mi²

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What is the difference in Fahrenheit degrees between a temperature of 0C and a temperature of 15C?
slamgirl [31]

Answer:

27^{\circ}F

Step-by-step explanation:

Use formula

F=1.8C+32

to convert Celsius to Fahrenheit.

When C_1=0^{\circ}C, then

F_1=1.8\cdot 0+32\\ \\F_1=32^{\circ}F

When C_2=15^{\circ}C, then

F_2=1.8\cdot 15+32\\ \\F_2=27+32=59^{\circ}F

Difference:

F_2-F_1=59^{\circ}F-32^{\circ}F=27^{\circ}F

8 0
3 years ago
Find the sum of the first 8 terms in the sequence 2 8 32 128
Zigmanuir [339]

the sequence is in multiples of 4 (2*4=8, 8*4=32, 32*4=128)

so 128*4=512, 512*4=2048, 2048*4=8192 & 8192*4=32768

2+8+32+128+512+2048+8192+32768=43690 

4 0
2 years ago
Mr. Vella can build a brick wall in 4 days. His apprentice can build the same wall in 6 days. After working alone for 3 days, Mr
Vitek1552 [10]
Mr. Vella can build the wall in 4 days, however only works on it for 3 days. That means that he has completed 75% of the and is leaving 25% for his apprentice.

We need to figure out how long it takes the apprentice to build 25% of a wall. We know he can build 100% of a wall in 6 days, so dividing 6 days by 4 will give us our answer.

6/4 = 3/2 = 1.5 days

It took the apprentice 1.5 days to finish the wall.
6 0
3 years ago
Look at the rectangle and the square:
OlgaM077 [116]

Answer:

Sam is incorrect

Step-by-step explanation:

We can calculate the lengths of the diagonals using Pythagoras' identity.

The diagonals divide the rectangle and square into 2 right triangles.

Consider Δ SRQ from the rectangle

SQ² = SR² + RQ² = 12² + 6² = 144 + 36 = 180 ( take square root of both sides )

SQ = \sqrt{180} ≈ 13.4 in ( to 1 dec. place )

Consider Δ ONM from the square

OM² = ON² + NM² = 6² + 6² = 36 + 36 = 72 ( take square root of both sides )

OM = \sqrt{72} ≈ 8.5 in ( to 1 dec. place )

Now 2 × OM = 2 × 8.5 = 17 ≠ 13.4

Then diagonal OM is not twice the length of diagonal SQ

5 0
2 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B60%7D%20%7D%7B%5Csqrt%5B3%5D%7B36%7D%20%7D" id="TexFormula1" title=
Margarita [4]
∛60
--------
∛36

=
∛5
------
∛3

=∛45
-----------
3

= 1.185
3 0
2 years ago
Read 2 more answers
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