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3 years ago

Solve the equation in the interval [0, 2π] 2 + Tanθ = 1

Mathematics

1 answer:

Klio2033 [76]3 years ago

5 0

Answer:

{3π/4 , 7π/4}

Step-by-step explanation:

2 + Tanθ = 1

tan θ = 1 -2

Tanθ = -1

θ = 3π/4 and 7π/4

You might be interested in

Komok [63]

Answer:

42.7 cm sq.

Step-by-step explanation:

small/large = 16 / 122

16/122 = S / 56

S = 56 * (16/122) = 7.34...

however not in the choice

ah ha..

You meant : 12.2 sq. cm : 16 sq. cm = small / large

so 12.2 / 16 = S / 56 cm

S = 42.7 sq. cm

8 0

3 years ago

Which equation is the inverse of 2(x - 2)2 = 8(7 + y)?

Marina86 [1]

Answer:

The inverse of $2(x - 2)^2 = 8(7 + y)$ is $y=\sqrt{(4x+28)}+2$

Step-by-step explanation:

Given equation : $2(x - 2)^2 = 8(7 + y)$

$\Rightarrow \frac{2(x-2)^2}{8}=7+y\\\Rightarrow \frac{2(x-2)^2}{8}-7=y$

Replace x with y and y with x

So, $\Rightarrow \frac{2(y-2)^2}{8}-7=x\\\Rightarrow \frac{2(y-2)^2}{8}=x+7\\\Rightarrow 2(y-2)^2=8(x+7)\\\Rightarrow (y-2)^2=4(x+7)\\\Rightarrow (y-2)=\sqrt{4(x+7)}\\\Rightarrow y=\sqrt{4(x+7)}+2\\\Rightarrow y=\sqrt{4x+28)}+2$

So, Option C is correct

Hence The inverse of $2(x - 2)^2 = 8(7 + y)$ is $y=\sqrt{(4x+28)}+2$

4 0

2 years ago

Solve the equations <br> 3x + 5y = 21 <br> -20x + 5y <br> show your work

Digiron [165]

Answer:

x=21/23

Step-by-step explanation:

Solve for x:

3x+5y=21−20x+5y

Add 20x to both sides:

3x+5y+20x=−20x+5y+21+20x

23x+5y=5y+21

Subtract 5y to both sides:

23x+5y+−5y=5y+21+−5y

23x=21

Divide both sides by 23:

x=21/23

8 0

3 years ago

50 PTS ANSWER ALL <3333333

11Alexandr11 [23.1K]

QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

${h}^{2} = {6}^{2} + {8}^{2}$

${h}^{2} = 36+ 64$

${h}^{2} = 100$

$h = \sqrt{100}$

$h = 10cm$

Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

${l}^{2} + {33}^{2} = {55}^{2}$

${l}^{2} = {55}^{2} - {33}^{2}$

${l}^{2} = 1936$

$l = \sqrt{1936}$

$l = 44cm$

Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the values to get,

$d=\sqrt{( - 1-2)^2+(3- - 1)^2}$

$d=\sqrt{( - 3)^2+(4)^2}$

$d=\sqrt{9+16}$

$d=\sqrt{25}$

$d = 5$

Answer: 5 units.

QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

$d=\sqrt{( - 3-2)^2+( - 3- 2)^2}$

$d=\sqrt{( - 5)^2+( - 5)^2}$

$d=\sqrt{25+25}$

$d=\sqrt{50}$

$d=5\sqrt{2}$

Answer: D

8 0

3 years ago

Read 2 more answers

The temperature on Monday was 78.8°C. The temperature on Tuesday was 6.6°C less than the temperature on Monday. What was the tem

geniusboy [140]

Answer:

72.2

Step-by-step explanation:

Monday: 78.8

Tuesday: 78.8 - 6.6 = 72.2

8 0

3 years ago