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makkiz [27]
3 years ago
10

G = {(5, 3), (2, 3), (6, 4)} Is G-1 a function and why?

Mathematics
1 answer:
rewona [7]3 years ago
7 0

The inverse relation G^(-1) is not a function. Why not? Because the y value y = 3 is paired up with more than one x value (x = 5, x = 2). The inverse relation G^(-1) is the set shown below

{(3,5), (3,2), (4,6)}

All I've done is swap the (x,y) values for each ordered pair to form the inverse relation. As you can see, x = 3 leads to multiple y value outputs which is why this relation is not a function. So in short, the answer is choice C. To have the inverse relation be a function, each value in the original domain must map to exactly one value in the range only. However that doesn't happen as the domain values map to an overlapping y value (y = 3).

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The argument is true by the law of syllogism

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Read 2 more answers
If trapezoid JKLM is translated according to the rule (x,y)—> (x+2, y - 6), what are the coordinates of point L
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Answer:

<em> ( x, y) is translation '2' units right and '6' units down </em>

<em> (x ,y))—> (x +2 ,y-6)</em>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Type of transformation                            change to co-ordinate point

vertical translation up 'd' units                (x,y)  changes to  (x  , y+d)

<em>vertical translation down 'd' units          (x,y)  changes to  (x  , y-d)</em>

Horizontal translation left 'c' units          (x,y)  changes to  (x-c  , y)

Horizontal translation right 'c' units            (x,y)  changes to  (x+c  , y)

Now by use above table

given data  ( x, y) is translation '2' units right and '6' units down

(x ,y))—> (x +2 ,y-6)

<u><em>Final answer:-</em></u>

<em> ( x, y) is translation '2' units right and '6' units down </em>

<em> (x ,y))—> (x +2 ,y-6)</em>

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