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sergeinik [125]

3 years ago

14

Please help me asap!!!!!!!!!!!!!!!!!!!!!!!!!

2 answers:

tankabanditka [31]3 years ago

5 0

A of the base=
6×6=36 square inches
A of four triangles=
9×6×2=108 square inches
108+36=144. As a result, the surface area of the clock is 144 square inches. Hope it help!

Yakvenalex [24]3 years ago

4 0

The answer is 144in squared

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What is the inverse of the function f(x)=1/9+2

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3 years ago

Find tan2θ if θ terminates in Quadrant IV and cosθ = 3/5.

natali 33 [55]

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$\cos( \alpha ) = \frac{3}{5} \\$

${sin}^{2}( \alpha ) = 1 - {cos}^{2} ( \alpha )$

${sin}^{2}( \alpha ) = 1 - ({ \frac{3}{5} })^{2} \\$

${sin}^{2}( \alpha ) = 1 - \frac{9}{25} \\$

${sin}^{2}( \alpha ) = \frac{25}{25} - \frac{9}{25} \\$

${sin}^{2}( \alpha ) = \frac{16}{25} \\$

$sin( \alpha )= ± \sqrt{ \frac{16}{25} } \\$

In Quadrant IV , sin is negative .

Thus ;

$sin( \alpha ) = - \sqrt{ \frac{16}{25} } \\$

$\sin( \alpha ) = - \frac{4}{5} \\$

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$\tan(2 \alpha ) = \frac{ \sin(2 \alpha ) }{ \cos(2 \alpha ) } \\$

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$\sin(2 \alpha ) = 2. \sin( \alpha ). \cos( \alpha )$

$\sin(2 \alpha ) = 2 \times ( - \frac{4}{5} ) \times ( \frac{3}{5} ) \\$

$\sin(2 \alpha ) = - \frac{24}{25} \\$

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$\cos(2 \alpha ) = {cos}^{2}( \alpha ) - {sin}^{2}( \alpha )$

$\cos(2 \alpha ) = ({ \frac{3}{5} })^{2} - ({ - \frac{4}{5} })^{2} \\$

$\cos(2 \alpha ) = \frac{9}{25} - \frac{16}{25} \\$

$\cos(2 \alpha ) = - \frac{7}{25} \\$

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$\tan(2 \alpha ) = \frac{ \sin(2 \alpha ) }{ \cos(2 \alpha ) } \\$

$\tan(2 \alpha ) = \frac{ - \frac{24}{25} }{ - \frac{7}{25} } \\$

$\tan(2 \alpha ) = - \frac{24}{25} \div - \frac{7}{25} \\$

$\tan(2 \alpha ) = - \frac{24}{25} \times - \frac{25}{7} \\$

$\tan(2 \alpha ) = \frac{24}{7} \\$

Thus the correct answer is (( C )) .

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4 0

3 years ago

Read 2 more answers

How would I start this?

solong [7]

Answer:

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So, the left end of the interval is 0, but 0 is not included in the interval.

The right end of the interval is infinity, but there is no such number, so "infinity" is not included in the interval.

"Not included" means you use round brackets ( ) for the corresponding end of the interval. ("Included" would mean you use square brackets [ ].)

So, the interval 0 < x < ∞ is written in interval notation as ...

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