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andrezito [222]
3 years ago
13

Jan's sister and mother have both had breast cancer. She is wondering if she should undergo genetic testing to check for a mutat

ion of the BRCA1 gene. A mutation in the BRCA1 gene is commonly associated with, but not guaranteed to cause, breast cancer. The presence of a mutation increases a patient's chances of getting breast cancer to about 85 percent, compared to a 13 percent risk in the general population. Costs may vary, but most labs charge patients or their insurance companies less than $3,000 to sequence the BRCA1 to look for mutations. Do you think that Jan should undergo genetic sequencing? Explain your answer.
Biology
2 answers:
Vlad1618 [11]3 years ago
7 0
Yes, Jan should undergo genetic sequencing.BRCA1/BRCA2 are the causes of 20-25% of all hereditary breast cancers, so if Jan's mother and sister both have breast cancer, then the odds are that she has BRCA1 as well.
Marta_Voda [28]3 years ago
7 0

Answer:

Jan should go through sequencing.

Explanation:

Jan already has a family history of breast cancer, which means that she already has a certain chance of experiencing this cancer in the future, for this reason, Jan should look for ways to decrease the risk factors for breast cancer to develop. develop into it. One of Jan's ways of taking precautions is through genetic sequencing, which can show her if she has a BRCA1 gene mutation.

However, as we already know, this procedure is very expensive and an accurate result is not guaranteed. With that we can say that Jan should do the sequencing if she has enough resources for that.

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If the frequency of the recessive allele for a gene is 0.3, calculate the expected frequency of heterozygotes in the next genera
Kisachek [45]
Q = recessive allele frequency = 0.3, and thus in H-W equilibrium there are ONLY two alleles, q (recessive) and
p (dominant). Therefore all of the p and q present for this gene in a population must account for 100% of this gene's alleles. And 100% = 1.00.
So p, the dominant allele frequency, must be equal to 1 - q --> p = 1 - q
p = 1 - 0.3 = 0.7.
Since heterozygotes are a combination of the p and q, we must again look at the frequencies of each genotype: p + q = 1, then (p+q)^2 = 1^2
So multiplying out (p+q)(p+q) = 1, we get: p^2+2pq+q^2 = 1 (all genotypes), where p^2 = frequency of homozygous dominant individuals, 2pq = frequency of heterozygous individuals, and q^2 = frequency of homozygous recessive individuals.
Therefore if the population is in H-W equilibrium, then the expected frequency of heterozygous individuals = 2pq = 2(0.7)(0.3)
2pq = 2(0.21) = 0.42, or 42% of the population.
Hope that helps you to understand how to solve population genetics problems!
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3 years ago
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Answer: Option A) inhibits

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Answer:

According to the law of conservation of matter, matter is never created or destroyed but it can change from one form to another. Most of the biomass in a food web gets converted at each trophic level and it no longer remains apart of the food web. Most of the biomass is released into the atmosphere in the form of heat and hence cannot be transferred to the other trophic level. Also, matter is used up by the organism itself and converted into different forms. Most of the matter might get accumulated in the soil when the organisms of a trophic level die.

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hope this helps :)

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