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postnew [5]
3 years ago
13

Pressure with Two Liquids, Hg and Water. An open test tube at 293 K is filled at the bottom with 12.1 cm of Hg, and 5.6 cm of wa

ter is placed above the Hg. Calculate the pressure at the bottom of the test tube if the atmospheric pressure is 756 mm Hg. Use a density of 13.55 g/cm3 for Hg and 0.998 g/cm3 for water. Give the answer in terms of dyn/cm2, psia, and kN/m2. See Appendix A.1 for conversion factors.
Business
1 answer:
Radda [10]3 years ago
8 0

Answer:

1170839.28 dyn/cm^2

16.9816 psia

117.083928 kN/m^2

Explanation:

To calculate the absolute pressure in the bottom of tube we need to sum the atmosferic and gauge pressure.

P_{abs}=P_{atm}+P_G

And the gauge pressure is given by the contributions of columns of water (P_{w}) and mercury(P_{Hg}), we can calculate the contribution of each column as:

P= \rho g h (*)

where \rho is the respective density, g gravity and h is height.

So we have all the data required to use the above equations (P_{atm}, height and density of each column) we only need to be carefully with the units.

For simplicity we can to express all pressure contributions in mmHg ( P_{atm}, P_{w} and P_{Hg}). Note that the units "x" mmHg  means the pressure at the bottom of a column of mercury of "x" mm high. For example, in this case we have a column 12.1 cm of Hg, that is a column of 121 mmHg (passing from cm to mm only requires multiply by 10) pressure exerted by that column is 121 mmHg.

Now pressure of 5.6 cm (56 mm) of water would be 56 mm of water, but it is not the same that mmHg, since the density of water is lower, the pressure exerted by 1 mm of water is lower than the exerted by 1 mm of Hg. The conversion between mmHg and mm of water is given by the relation between the densities.

mmHg=\frac{\rho_w*mmH_2O}{\rho_{Hg}}

mmHg=\frac{0.998*mmH_2O}{13.55}=0.0737 mmH_2O

And pressure of water in mmHg is

0.0737*56=4.1246 mmHg

The absolute pressure is:

P_{abs}=P_{atm}+P_G= 756 + 121 + 4.1246  = 881.1246 mmHg = 88.11246cmHg

To pass to dyn/cm^2 units we need to use the equation (*)

P= \rho g h = 13.55 \frac{g}{cm^3} * 980.665 \frac{cm}{s^2} * 88.11246 cmHg = 1170839.28 \frac{g}{cm s^2} = 1170839.28 \frac{dyn}{cm^2}

Note: We need to use cm Hg for units coherence

Now passing from dyn/cm^2 to kN/m^2 (or kPa) we need to consider that 1 dyn is 10^{-8} kN and 1 cm^2 is 10^{-4} m^2.  

1170839.28 \frac{dyn}{cm^2} * \frac{10^{-8}kN}{1 dyn}*\frac{cm^2}{10^{-4}m^2}=117.083928kN/m^2

Now passing kN/m^2 to psia. We need to consider that 1 psia is 6.89476.

117.083928kN/m^2*\frac{1psia}{6.89476kN/m^2}=16.9816 psia

 

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When the effective-interest method of bond discount amortization is used,
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Answer: C. interest expense will not be a constant dollar amount over the life of the bond.

Explanation:

When a bond is sold at a discount, the discount will have to be amortized over the life of the bond to ensure that it reaches par at maturity.

As a result, the interest expense will be based on a larger figure every year which would mean that it would have to be larger each time. t will therefore not be a constant dollar amount over the life of the bond.

6 0
3 years ago
A furnace repair team services a design capacity of 6 furnaces per day with an effective capacity of 5 furnaces per day. What is
VashaNatasha [74]

Answer:

66.7%

Explanation:

Given that,

Design capacity = 6 furnaces per day

Effective capacity = 5 furnaces per day

Efficiency ratio if it repairs an average of 4 furnaces per day:

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= (4 per day ÷ 6 per day) × 100

= 0.667 × 100

= 66.7%

Therefore, the efficiency ratio is 66.7 percent.

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3 years ago
Suppose that Dunkin Donuts reduces the price of its regular coffee from $2 to $1 per cup, and as a result, the quantity sold per
harkovskaia [24]

Answer:price elasticity of demand for Dunkin Donuts’ regular coffee is 1.8

Explanation: Using the midpoint formnulae

Price elasticity of Demand =percentage change in quantity demanded/ Percentage change in price.

Percentage change in quantity = new quantity  - old quantity  / (new quantity + old quantity)/2  x 100

= 40-10/(40+10)/ 2 = 30 /25 = 1.2 x 100 =120%

Percentage change in price  = new price   - old price   / new price + old price)/2   x 100

= 1- 2 / (1+2)/2= -1/1.5x 100 = -66.67 %

Price elasticity of Demand =percentage change in quantity demanded/ Percentage change in price.

= 120%/-66.67%= -1.79 = -1.8

For Price elasticity of demand, the sign is not included and the basis for elasticity is on the value itself . here we can conclude that the Price elasticity of demand for Dunkin donut is 1.8 and elastic because a fall in price led to an increase in amount being sold.

3 0
3 years ago
Exercise 11-1 Compute the Return on Investment (ROI) [LO11-1] Alyeska Services Company, a division of a major oil company, provi
Jobisdone [24]

Answer:

1. 28.09 %

2.0.50 times

3.13.97 %

Explanation:

Margin = Profit / Sales × 100

            = $ 5,000,000 / $ 17,800,000 × 100

            = 28.09 % (2 decimal places.)

Turnover = Sales / Total Assets

               = $ 17,800,000 / $ 35,800,000

               = 0.50 times (2 decimal places.)

Return on investment = Divisional Profit Contribution / Assets employed in the  division × 100

                                    =  $ 5,000,000 / $ 35,800,000 × 100

                                    = 13.97 % (2 decimal places.)

8 0
3 years ago
Rather than purchase new equipment, the marketing manager argues that the company's marketing strategy should be changed. Rather
Kitty [74]

Answer:

Break-even point (dollars)= $1,104,000

Explanation:

Giving the following information:

The company's new monthly fixed expenses would be $331,200.

Selling price= 24

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With this information we can calculate the break-even point both in units and dollars:

Break-even point= fixed costs/ contribution margin

Break-even point= 331,200/ (24 - 16.8)= 46,000 units

Break-even point (dollars)= fixed costs/ contribution margin ratio

Break-even point (dollars)= 331,200/ (7.2/24)= $1,104,000

5 0
3 years ago
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