Answer:
The cost of 6 cans of soup = $7.8
Step-by-step explanation:
The cost of 10 cans of soup = $13
The number of cans needed for the soup = 6
Now, Cost of 1 can of soup =
= $13 / 10 =$1.3
⇒The cost of 1 can of soup is $1.3
Now, The cost of 6 cans of soup = 6 x Cost of 1 can
⇒ 6 x $1.3 = $7.8
Hence, the cost of 6 cans of soup = $7.8
Answer:
Give tjbears branliest
Step-by-step explanation:
First option is the correct answer
The answer would be 16 S'mores and the limiting reactant would be the grahams.
(This is assuming that S'mores would need 2 grahams, 1 marshmallow and 1 chocolate piece.)
Limiting reactant would be the reactant that runs out first.
Let's take your problem into account and see what we have:
48 marshallows
32 grahams (2 x 16 per pack)
45 chocolate pieces (5 x 15 pieces per bar)
Since need 2 of the grahams per S'more then the maximum yield of the grahams is 16 S'mores.
The maximum yield of marshmallows is 48.
The maximum yield of chocolate is 45.
Since you cannot make S'mores without the grahams, then you can only make 16 S'mores before the grahams run out.